The variable x is twice the value of the variable y and the sum of x and y is 42 solve for x and y.
2 answers:
Answer:
x=28 x=14
Step-by-step explanation:
x+y=42
2y=x
My method of doing this is a little unorthodox so this is probably going to make no sense... but here goes...
42/2=21
21*(2/3)=14
14*2=28
Write two equations with the given information:
1) x = 2y ( x is twice the value of y)
2) x + y = 42
Replace x in the second equation with the value of x in the first equation:
2y + y = 42
Simplify:
3y = 42
Divide both sides by 3:
y = 42 / 3
y = 14
Now we have the value for Y, solve for x by replacing y with 14:
x = 2y
x = 2(14)
x = 28
X = 28 and y = 14
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Answer:
the first term is a1
the distance between the numbers is d
we have:
a5 = a1 + 4d = 23
a12 = a1 + 11d = 72
so we have the equation:
a1 + 4d = 23
a1 + 11d = 72
=> a1 = -5
d = 7
=> an = -5 + 7(n - 1) = 7n - 12
with an = 7n - 12
=> a2 = 2
a3 = 9
so the first three terms is -5; 2; 9
You would -a to get 6x=5-a then divide by 6 which you would get your final answer which is x=5-a/6