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JulijaS [17]
3 years ago
14

The variable x is twice the value of the variable y and the sum of x and y is 42 solve for x and y.

Mathematics
2 answers:
Lunna [17]3 years ago
8 0

Answer:

x=28     x=14

Step-by-step explanation:

x+y=42

2y=x

My method of doing this is a little unorthodox so this is probably going to make no sense... but here goes...

42/2=21

21*(2/3)=14

14*2=28

Oksi-84 [34.3K]3 years ago
4 0

Write two equations with the given information:

1) x = 2y ( x is twice the value of y)

2) x + y = 42

Replace x in the second equation with the value of x in the first equation:

2y + y = 42

Simplify:

3y = 42

Divide both sides by 3:

y = 42 / 3

y = 14

Now we have the value for Y, solve for x by replacing y with 14:

x = 2y

x = 2(14)

x = 28

X = 28 and y = 14

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8 0
2 years ago
Hi please help me as soon as possible:
sammy [17]

Answer:

Percentage = 14.2%

Step-by-step explanation:

<u>Given the following data;</u>

Cost of plane ticket = £588

Airport tax = $130

£1 = $1.34

To find the percentage of the total cost spent on airport tax;

First of all, we would convert the ticket cost in pounds (£) to dollars ($).

Cost of plane ticket = £588 to $ = 588 * 1.34 = $787. 92

Total cost = Cost of plane ticket + Airport tax

Total cost = 787. 92 + 130

Total cost = $917.92

Percentage \; cost = \frac {130}{917.92} * 100

Percentage  = 0.1416 * 100

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6 0
3 years ago
A bag contains 10 marbles,7 of which are black and 3 are red.three marbles are drawn at one after the other.find the probability
S_A_V [24]
<h3>Answer:  17/24</h3>

==========================================================

Explanation:

We have these four cases or possible outcomes

  • Case 1) We select 0 black marbles and 3 red marbles.
  • Case 2) We select 1 black marble and 2 red marbles.
  • Case 3) We select 2 black marbles and 1 red marble.
  • Case 4) We select 3 black marbles and 0 red marbles.

Let's calculate the probability for case 4.

There are 7 black marbles out of 10 total. The probability of picking black is 7/10. If no replacement is made, then 6/9 is the probability of picking black again (subtract 1 from the numerator and denominator separately). Finally, 5/8 is the probability of getting black a third time.

The probability of getting 3 black marbles in a row is

(7/10)*(6/9)*(5/8) = (7*6*5)/(10*9*8) = 210/720 = 7/24.

That fraction 7/24 means that if you had 24 chances, then you expect about 7 of them will lead to getting three black marbles in a row (aka case 4). Therefore, 24-7 = 17 occurrences are expected where we get cases 1 through 3 occur in some fashion (pick one case only).

Notice how cases 1 through 3 encapsulate the phrasing "at most 2 black marbles" which is another way of saying "2 black marbles is the highest we can go".

So that's why the answer is 17/24.

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