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3 years ago

18. Use the distributive property to write an equivalent expression to: -(2x + 3y)

Mathematics

1 answer:

nalin [4]3 years ago

4 0

Answer:

Step-by-step explanation:

-(2x + 3y)

= -2x - 3y

............

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The coordinates of the vertices of the triangle are (–8, 8), (–8, –4), and . Consider QR the base of the triangle. The measure o

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Which of the following is the solution to the system of equations shown below?

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2 years ago

The distance to the nearest exit doir is no more than 150 feet. Use d to represent the distance in feet to the nearest exit door

il63 [147K]

Answer: $d\leq150$

Step-by-step explanation:

1. You have the following information given in the problem:

- The distance to the nearest exit door is no more than 150 feet.

- $d$ represents the distance to the nearest exit door, in feet.

2. Therefore, keeping the information above on mind, you know that the distance to the nearest exit door ( $d$ ) must be less than or equal to 150 feet, then, you can express this as following:

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3 years ago

Limit definition for slope of the graph, equation of tangent line point for f(x)=2x^2 at x=(-1)

Tems11 [23]

The slope of the tangent line to $f$ at $x=-1$ is given by the derivative of $f$ at that point:

$f'(-1)=\displaystyle\lim_{x\to-1}\frac{f(x)-f(-1)}{x-(-1)}=\lim_{x\to-1}\frac{2x^2-2}{x+1}$

Factorize the numerator:

$2x^2-2=2(x^2-1)=2(x-1)(x+1)$

We have $x$ approaching -1; in particular, this means $x\neq-1$ , so that

$\dfrac{2x^2-2}{x+1}=\dfrac{2(x-1)(x+1)}{x+1}=2(x-1)$

Then

$f'(-1)=\displaystyle\lim_{x\to-1}\frac{2x^2-2}{x+1}=\lim_{x\to-1}2(x-1)=2(-1-1)=-4$

and the tangent line's equation is

$y-f(-1)=f'(-1)(x-(-1))\implies y-4x-2$

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2 years ago