All categories

3 years ago

Mke y the subject of the formula. w=x^2-2yz

Mathematics

1 answer:

charle [14.2K]3 years ago

7 0

Answer:

W = x^2 - 2yz / - w

0 = x^2 - 2yz - w / +2yz

2yz = x^2 - w // 2z

y = (x^2 -w ) / 2z

So correct answer is D

You might be interested in

A/b=2/5 and b/c=3/8 find a/c

m_a_m_a [10]

Answer:

$\frac{a}{c}$ = $\frac{3}{20}$

Step-by-step explanation:

$\frac{a}{c}$ = $\frac{a}{b}$ × $\frac{b}{c}$ = $\frac{2}{5}$ × $\frac{3}{8}$ = $\frac{6}{40}$ = $\frac{3}{20}$

3 0

3 years ago

SOLVE THE EQUATION −9(x + 6) + 60 = 13 − 10x

yuradex [85]

Answer:

x=7

Step-by-step explanation:

−9(x + 6) + 60 = 13 − 10x

Distribute

−9x -54 + 60 = 13 − 10x

Combine like terms

-9x +6 = 13 -10x

Add 10x to each side

-9x+10x +6 = 13-10x+10x

x +6 = 13

Subtract 6 from each side

x+6-6=13-6

x = 7

7 0

3 years ago

Please help asap (:

Korolek [52]

For this case we first define the variable:
x = number of terms.
The equation that models the problem is:
f (x) = 3.4 - 0.6x
We have then that the first four terms are:
x = 1
f (1) = 3.4 - 0.6 (1) = 3.4 - 0.6 = 2.8
x = 2
f (2) = 3.4 - 0.6 (2) = 3.4 - 1.2 = 2.2
x = 3
f (3) = 3.4 - 0.6 (3) = 3.4 - 1.8 = 1.6
x = 4
f (4) = 3.4 - 0.6 (4) = 3.4 - 2.4 = 1
Answer:
The rule for the sequence is:
f (x) = 3.4 - 0.6x
option 1

7 0

3 years ago

Read 2 more answers

Evaluate the expression 7 + 10 /5

Anestetic [448]

Answer:

Step-by-step explanation:

Use PEMDAS (Parenthesis, exponent, multiplication, devision, addition, subtraction)

So....

7 + 2 .... Simplified ( 10/5 =2)

9 ..... Added

Hope this helps!

4 0

3 years ago

Read 2 more answers

For what values of θ on the polar curve r=θ, with 0≤θ≤2π , are the tangent lines horizontal? Vertical?

Bond [772]

Given that $r=\theta$ , then $r'=1$

The slope of a tangent line in the polar coordinate is given by:

$m= \frac{r'\sin\theta+r\cos\theta}{r'\cos\theta-r\sin\theta}$

Thus, we have:

$m= \frac{\sin\theta+\theta\cos\theta}{\cos\theta-\theta\sin\theta}$

Part A:

For horizontal tangent lines, m = 0.

Thus, we have:

$\sin\theta+\theta\cos\theta=0 \\ \\ \theta\cos\theta=-\sin\theta \\ \\ \theta=- \frac{\sin\theta}{\cos\theta} =-\tan\theta$

Therefore, the values of θ on the polar curve r = θ, with 0 ≤ θ ≤ 2π, such that the tangent lines are horizontal are:

θ = 0

θ = 2.02875783811043

θ = 4.91318043943488

Part B:

For vertical tangent lines, $\frac{1}{m} =0$

Thus, we have:

$\cos\theta-\theta\sin\theta=0 \\ \\ \Rightarrow\theta\sin\theta=\cos\theta \\ \\ \Rightarrow\theta= \frac{\cos\theta}{\sin\theta} =\sec\theta$

Therefore, the values of θ on the polar curve r = θ, with 0 ≤ θ ≤ 2π, such that the tangent lines are vertical are:

θ = 4.91718592528713

3 0

3 years ago