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Nostrana [21]
3 years ago
11

Mke y the subject of the formula. w=x^2-2yz

Mathematics
1 answer:
charle [14.2K]3 years ago
7 0

Answer:

W = x^2 - 2yz / - w

0 = x^2 - 2yz - w / +2yz

2yz = x^2 - w // 2z

y = (x^2 -w ) / 2z

So correct answer is D

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A/b=2/5 and b/c=3/8 find a/c​
m_a_m_a [10]

Answer:

\frac{a}{c} = \frac{3}{20}

Step-by-step explanation:

\frac{a}{c} = \frac{a}{b} × \frac{b}{c} = \frac{2}{5} × \frac{3}{8} = \frac{6}{40} = \frac{3}{20}

3 0
3 years ago
SOLVE THE EQUATION<br> −9(x + 6) + 60 = 13 − 10x
yuradex [85]

Answer:

x=7

Step-by-step explanation:

−9(x + 6) + 60 = 13 − 10x

Distribute

−9x -54 + 60 = 13 − 10x

Combine like terms

-9x +6 = 13 -10x

Add 10x to each side

-9x+10x +6 = 13-10x+10x

x +6 = 13

Subtract 6 from each side

x+6-6=13-6

x = 7

7 0
3 years ago
Please help asap (:
Korolek [52]
For this case we first define the variable:
 x = number of terms.
 The equation that models the problem is:
 f (x) = 3.4 - 0.6x
 We have then that the first four terms are:
 x = 1
 f (1) = 3.4 - 0.6 (1) = 3.4 - 0.6 = 2.8
 x = 2
 f (2) = 3.4 - 0.6 (2) = 3.4 - 1.2 = 2.2
 x = 3
 f (3) = 3.4 - 0.6 (3) = 3.4 - 1.8 = 1.6
 x = 4
 f (4) = 3.4 - 0.6 (4) = 3.4 - 2.4 = 1
 Answer:
 
The rule for the sequence is:
 
f (x) = 3.4 - 0.6x
 option 1
7 0
3 years ago
Read 2 more answers
Evaluate the expression<br>7 + 10 /5​
Anestetic [448]

Answer:

9

Step-by-step explanation:

Use PEMDAS (Parenthesis, exponent, multiplication, devision, addition, subtraction)

So....

7 + 2 .... Simplified ( 10/5 =2)

9 ..... Added

Hope this helps!

4 0
3 years ago
Read 2 more answers
For what values of θ on the polar curve r=θ, with 0≤θ≤2π , are the tangent lines horizontal? Vertical?
Bond [772]
Given that r=\theta, then r'=1

The slope of a tangent line in the polar coordinate is given by:

m= \frac{r'\sin\theta+r\cos\theta}{r'\cos\theta-r\sin\theta}

Thus, we have:

m= \frac{\sin\theta+\theta\cos\theta}{\cos\theta-\theta\sin\theta}



Part A:

For horizontal tangent lines, m = 0.

Thus, we have:

\sin\theta+\theta\cos\theta=0 \\  \\ \theta\cos\theta=-\sin\theta \\  \\ \theta=- \frac{\sin\theta}{\cos\theta} =-\tan\theta

Therefore, the <span>values of θ on the polar curve r = θ, with 0 ≤ θ ≤ 2π, such that the tangent lines are horizontal are:

</span><span>θ = 0

</span>θ = <span>2.02875783811043
</span>
θ = <span>4.91318043943488



Part B:

For vertical tangent lines, \frac{1}{m} =0

Thus, we have:

\cos\theta-\theta\sin\theta=0 \\  \\ \Rightarrow\theta\sin\theta=\cos\theta \\  \\ \Rightarrow\theta= \frac{\cos\theta}{\sin\theta} =\sec\theta

</span>Therefore, the <span>values of θ on the polar curve r = θ, with 0 ≤ θ ≤ 2π, such that the tangent lines are vertical are:

</span>θ = <span>4.91718592528713</span>
3 0
3 years ago
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