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Anton [14]
3 years ago
5

3-7*(16/2+3-1)+6 showing this work

Mathematics
1 answer:
lord [1]3 years ago
4 0

Answer:-61

Step-by-step explanation:

3-7(16/2+3-1)+6

3-7(8+3-1)+6

3-7(10)+6

3-70+6

-67+6

-61

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Which expression represents -8x^2+54x+140 in factored form?
Elenna [48]

Answer:

D. (x+2)(-8x+70)​

Step-by-step explanation:

-8x^2+54x+140

Factor out -2

-2(4x^2+27x+70)

Factor

-2(x+2)(4x-35)

Option D is the same answer if we multiply -2 in the second term

(x+2) (-8x+70)

7 0
2 years ago
Please answer this question!
Aleks [24]
406 divided by 140 makes 2.9 multiply that 100 and you arrive at 290%. Hope this helps!
8 0
3 years ago
4 – (2y + 5) = 3(1 – 4y) show steps please
Lelu [443]

Answer/Step-by-step explanation:

Let's solve your equation step-by-step.

4−(2y+5)=3(1−4y)

Step 1: Simplify both sides of the equation.

4−(2y+5)=3(1−4y)

4+−1(2y+5)=3(1−4y)(Distribute the Negative Sign)

4+−1(2y)+(−1)(5)=3(1−4y)

4+−2y+−5=3(1−4y)

4+−2y+−5=(3)(1)+(3)(−4y)(Distribute)

4+−2y+−5=3+−12y

(−2y)+(4+−5)=−12y+3(Combine Like Terms)

−2y+−1=−12y+3

−2y−1=−12y+3

Step 2: Add 12y to both sides.

−2y−1+12y=−12y+3+12y

10y−1=3

Step 3: Add 1 to both sides.

10y−1+1=3+1

10y=4

Step 4: Divide both sides by 10.

10y

10

=

4

10

y=

2

5

Answer:

y= 2/5

yw

6 0
3 years ago
Read 2 more answers
Given that events A and B are independent with P(A)=0.3P(A)=0.3 and P(A\cap B)=0.27P(A∩B)=0.27, determine the value of P(B)P(B),
Stolb23 [73]

Answer:

0.9

Step-by-step explanation:

Since A and B are independent  hence;

P(A∩B) = P(A)P(B)

Given the following

P(A∩B) = 0.27

P(A) = 0.3

Required

P(B)

Substitute into the formula;

P(B) = P(A∩B)/P(A)

P(B) = 0.27/0.3

P(B) = 0.9

Hence the value of P(B) is 0.9

6 0
3 years ago
How do i factor 2x^2+11x+5
ira [324]
For simple integer factors as this one has, you want to find two values for the quadratic in the form ax^2+bx+c.   Let the two values be j and k.  These two values must satisfy two conditions.

jk=ac=10 and j+k=b=11, so j and k must be 1 and 10.

Now replace bx with jx and kx...

2x^2+x+10x+5  now factor 1st and 2nd pair of terms.

x(2x+1)+5(2x+1)

(x+5)(2x+1)
7 0
3 years ago
Read 2 more answers
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