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aksik [14]
3 years ago
12

A girl of normal stature is born to two parents with achondroplasia who have very short stature, especially disproportionately s

hort arms and legs. What is the probability (by Punnett Square analysis) that any pregnancy this girl eventually has will result in the birth of an infant with achondroplasia if her partner also has normal stature? (HINT: achondroplasia is an autosomal dominant trait)
Biology
1 answer:
Tcecarenko [31]3 years ago
5 0
Answer: 100% (4/4)
Explanation: Since the woman’s trait is dominant it will mask the normal stature in all their offspring. For example, A = achondroplasia trait, a = normal stature. It is very possible that the woman carries the trait and her offspring who may not possess it can pass it on to their offspring
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What holds the 2 chromatids that form a chromosome together ?
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Blue moon beans produce beans that are either the dominant color blue or the recessive color white The bean pods for this specie
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Answer:

a) 0.316

b) 0.105

c) 0.035

d) 0.0117

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Explanation:

When two heterozygous plants with genotype Bb are crossed, following offspring are produced

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so the probability of blue offspring is \frac{3}{4} and the probability of white offspring is \frac{1}{4}

a) Probability of all 4 peas as blue

\frac{3}{4} * \frac{3}{4} * \frac{3}{4} * \frac{3}{4} \\= \frac{81}{256} \\= 0.316

b) Probability of 3 blue and 1 white

\frac{3}{4} * \frac{3}{4}* \frac{3}{4}* \frac{1}{4}\\= \frac{27}{256} \\= 0.105

c) Probability of 2 blue and 2 white

\frac{3}{4} * \frac{3}{4}* \frac{1}{4}*\frac{1}{4}\\= 0.035

d) Probability of 1 blue and 3 white

\frac{3}{4} * \frac{1}{4} * \frac{1}{4}* \frac{1}{4}\\= \frac{3}{256} \\= 0.0117

e) Probability of all white

\frac{1}{4} * \frac{1}{4} * \frac{1}{4} * \frac{1}{4} \\= \frac{1}{256} \\= 0.0039

7 0
3 years ago
HOW IS MALARIA SPREAD?
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Malaria is spread by female Anopheles mosquitos. Hope this helps :) 
5 0
3 years ago
Read 2 more answers
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