First, third, fifth, and sixth answer
First, we arrange the data from least to greatest:
90, 100, 100, 200, 203, 224, 233, 237, 245, 257, 264, 265, 265, 266, 277, 279, 285, 288, 288, 290, 290, 291, 291, 300
There are 24 data all in all. The mean is calculated by dividing by 24 the sum of all the data.
mean = (5828)/24242.83
The median of the number of jumps is the mean of the 12th and 13th term.
265
Answer:
Total impedance in circuit = 8 - 2j ohms
Step-by-step explanation:
Given:
Circuit one = 1 + 3j ohms
Circuit two = 7 - 5j ohms
Find:
Total impedance in circuit
Computation:
Total impedance in circuit = Circuit one + Circuit two
Total impedance in circuit = 1 + 3j + 7 - 5j
Total impedance in circuit = 8 - 2j ohms
What grade are you in? I don't believe I have learned this yet!