Recall your d = rt, distance = rate * time
now, if say, by the time they meet, Mr Cunningham has travelled "d" miles, that means Mrs Cunningham must also had travelled "d" miles as well.
However, he left 3 hours earlier, so by the time he travelled "d" miles, and took say "t" hours, for her it took 3 hour less, because she started driving 3 hours later, so, she's been on the road 3 hours less than Mr Cunningham, so by the time they meet, Mrs Cunningham has travelled then "t - 3" hours.
Simplify
Let's simplify step-by-step.
x(5)−3(x−4)
Distribute:
=x(5)+(−3)(x)+(−3)(−4)
=5x+−3x+12
Combine Like Terms:
=5x+−3x+12
=(5x+−3x)+(12)
=2x+12
Answer:
=2x+12
He used 53 pounds. I got this by using two equations.
a+b=117
and
5.8a+4.1b= 569.8
I took the first equation and subtracted 'b' so the equation looked like a=117-b.
I then plugged in 117-b into the second equation, so it ended up looking like this:
5.8 (117-b)=569.8
5.8 times 117 is 678.6. And 5.8 times negative b is negative 5.8b.
The equation now looks like this:
678.6-5.8b+4.1b=569.8
Add like terms
678.6-1.7b=569.8
Then subtract 678.6 from both sides
-1.7b= -108.8
divide each side by -1.7
you get b= 64.
But because you are looking for how many pounds for a, subtract 64 from 117. You get 53. 53 is the answer.
Order.
9, 12, 12, 14, 15, 16, 18, 21
Now split into quarters.
9, 12, 12, 14, 15, 16, 18, 21
| | |
(1) (3)
Determine the values of (1) and (3) by using medians.
14 + 12 + 12 + 9 / 4
47 / 4
approx. 12
So Q1 = 12.
15 + 16 + 18 + 21 / 4
70 / 4
approx. 17
Therefore the answer is C I think. I have not done this ever before. All the knowledge I did was from research lol