Given :
A particle moves in the xy plane starting from time = 0 second and position (1m, 2m) with a velocity of v=2i-4tj .
To Find :
A. The vector position of the particle at any time t .
B. The acceleration of the particle at any time t .
Solution :
A )
Position of vector v is given by :

B )
Acceleration a is given by :

Hence , this is the required solution .
Answer:
(x - 9)(x + 3)
Step-by-step explanation:
Given
x² - 6x - 27
Consider the factors of the constant term (- 27) which sum to give the coefficient of the x- term (- 6)
The factors are - 9 and + 3, since
- 9 × 3 = - 27 and - 9 + 3 = - 6, thus
x² - 6x - 27 = (x - 9)(x + 3)
step-by-step explanation: the increase = 204 - 120
increase = 84
percent increase = 84/120
percent increase = 70% so of course the percentage is 70% ( I hope this helps you )
Answer:
Outlier!! I know it sounds like a cat poster but it's true
Step-by-step explanation: