Answer:
ANY NUMBER THAT HAS A X BEHIND IT..
Examples
1x
7x
15803x
104762836297x
17.
x = -2 is not a solution of -1 < x < 5 because -2 < -1 (-1 < -2 < 5 FALSE).
18.
m = 5 is a solution of 5 ≤ m because 5 ≤ 5 ( 5 ≤ m → m ≥ 5 greater than 5 or equal 5, 5 is equal 5)
19.
k = 10 is not solution of 2k - 3 < 1 because:
put the value of k to the inequality:
2(10) - 3 < 1
20 - 3 < 1
17 < 1 FALSE
9514 1404 393
Answer:
(d) 5a²
Step-by-step explanation:
![\displaystyle\sqrt[3]{125a^6}=\sqrt[3]{5^3a^6}=\sqrt[3]{(5a^2)^3}=\boxed{5a^2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Csqrt%5B3%5D%7B125a%5E6%7D%3D%5Csqrt%5B3%5D%7B5%5E3a%5E6%7D%3D%5Csqrt%5B3%5D%7B%285a%5E2%29%5E3%7D%3D%5Cboxed%7B5a%5E2%7D)
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The applicable rules of exponents are ...
(a^b)^c = a^(bc)
∛a = a^(1/3)
The formula is
a^3 - b^2 = (a - b)(a^2 + ab + b^2) so plugging in the given values:-
a = cube root of 125 = 5 and b = cube root of 27 = 3 , we get:-
125 - 27 = (5 - 3)(5^2 + 5*3 + 3^2)
= 2 * 49
= 98 answer
If you write

, you'll notice this is really just a quadratic equation that can be factorized:

So you have

and