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elena-14-01-66 [18.8K]
2 years ago
7

HELPPPPPPP MEEEEE BUT PUT THE CORRECT ANSWER

Mathematics
1 answer:
Elenna [48]2 years ago
3 0

Answer:

\sf 3\left[-x+\left(2x+1\right)\right]=x-1

\sf 3\left(-x+2x+1\right)=x-1

Combine like terms:

\sf -x+2x=x

\sf 3\left(x+1\right)=x-1

Expand:

\sf 3x+3=x-1

Subtract 3 from both sides:

\sf 3x+3-3=x-1-3

\sf 3x=x-4

Subtract x from both sides:

\sf 3x-x=x-4-x

\sf 2x=-4

Divide both sides by 2:

\sf \cfrac{2x}{2}=\cfrac{-4}{2}

\boxed{\boxed{ \sf x=-2}}

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The U.S. Bureau of Labor Statistics reports that 11.3% of U.S. workers belong to unions. Suppose a sample of 400 U.S. workers is
lorasvet [3.4K]

Answer:

1 is the answer

Step-by-step explanation:

Given that the U.S. Bureau of Labor Statistics reports that 11.3% of U.S. workers belong to unions.

H_0: p=0.113\\H_a: p >0.113

(Right tailed test for testing of a sample proportion with population proportion)

Suppose a sample of 400 U.S. workers is collected in 2014 to determine whether union efforts to organize have increased union membership at 0.025 level of significance.

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1 is the answer.

6 0
3 years ago
Which graph represents the solution to the inequality x+3 greater than or equal to 2?
Shalnov [3]

Answer:

x+3\ge 2=\begin{bmatrix}\mathrm{Solution:}\:&\:x\ge \:\:-1\:\\ \:\:\mathrm{Interval\:Notation:}&\:[-1,\:\infty \:\:)\end{bmatrix}

Please check the attached graph.

Step-by-step explanation:

We know that 'greater than or equal' is represented as '≥'.

Thus, inequality ''x+3 greater than or equal to 2'' is represented as:

x+3\ge 2

<u><em>Solving inequality</em></u>

x+3\ge 2

subtract 3 from both sides

x+3-3\ge \:2-3

simplify

x\ge \:-1

Thus,

x+3\ge 2=\begin{bmatrix}\mathrm{Solution:}\:&\:x\ge \:\:-1\:\\ \:\:\mathrm{Interval\:Notation:}&\:[-1,\:\infty \:\:)\end{bmatrix}

Please check the attached graph.

3 0
3 years ago
The figure below shows a parallelogram ABCD. Side AB is parallel to side DC and side AD is parallel to side BC: A quadrilateral
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Step-by-step explanation:

According to the ASA (Angle-Side-Angle) postulate, if two angles and the included side of one triangle are congruent to two angles and the included side of another triangle, then the triangles are congruent to each other. '

Here Given: ABCD is a parallelogram

That is, AB ║ CD and AD ║ BC

We have to prove that:The parallelogram ABCD has two pairs of opposite sides equal, that is, AB ≅ CD and AD ≅ BC.

Here BD is the diagonal of the parallelogram ABCD ( shown in the below figure)

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∠ABD ≅ ∠CDB ( alternative interior angles made on parallel lines by the same transversal BD)

BD ≅ BD ( Reflexive )

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Answer:

49

Step-by-step explanation:

7x7=49

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