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3 years ago

Easy Question, Easy pointsTopic: VolumeFocus on question 12

Mathematics

2 answers:

madreJ [45]3 years ago

5 0

Answer:

0.6 meters CUBED

Step-by-step explanation:

hope it helps

anyanavicka [17]3 years ago

4 0

Answer: 0.6 meters cubed.

Step-by-step explanation:

To find the answer to this, first find the volume of the cube.

Volume is equal to the side cubed. In this case, 1 cubed is 1, so the area of the cube is 1 meter cubed.

The depth of the water is 0.4 meters, so the water makes a shape of a rectangular prism, where the length and width are 1 meter, and the height is 0.4 meters.

The volume of a rectangular prism is l*w*h, so the volume of this rectangular prism is 0.4 * 1 * 1, or 0.4 meters cubed.

As such, the volume of the air in the tank is 1 - 0.4, or 0.6 meters cubed.

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A machine fills 75 bottles of water each minute. Write an equation to represent the number of bottles b of water the machine can

Len [333]

Answer:

b = 75m

Step-by-step explanation:

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3 years ago

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Which of the following ordered pairs could represent the x-intercept of a function?

bearhunter [10]

The answer is (15,0) because the format is (x,y) so (15,0) means that it is on the x axis only !

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3 years ago

A certain restaurant always overbooks. If possible. At 7:00 pm the restaurant can seat 50 parties, but takes reservations for 53

oee [108]

Answer:

The probability that the restaurant can accommodate all the customers who do show up is 0.3564.

Step-by-step explanation:

The information provided are:

At 7:00 pm the restaurant can seat 50 parties, but takes reservations for 53.
If the probability of a party not showing up is 0.04.
Assuming independence.

Let X denote the number of parties that showed up.

The random variable X follows a Binomial distribution with parameters n = 53 and p = 0.96.

As there are only 50 sets available, the restaurant can accommodate all the customers who do show up if and only if 50 or less customers showed up.

Compute the probability that the restaurant can accommodate all the customers who do show up as follows:

$P(X\leq 50)=1-P(X>50)\\=1-P(X=51)-P(X=52)-P(X=53)\\=1-[{53\choose 51}(0.96)^{51}(0.04)^{53-51}]-[{53\choose 52}(0.96)^{52}(0.04)^{53-52}]\\-[{53\choose 53}(0.96)^{53}(0.04)^{53-53}]\\=1-0.27492-0.25377-0.11491\\=0.3564$

Thus, the probability that the restaurant can accommodate all the customers who do show up is 0.3564.

7 0

3 years ago

The statement is either true in all cases or false. If false, construct a specific example to show that the statement is not alw

natali 33 [55]

Answer: The correct option is (B).

True. The vector V₃ is a linear combination of V₁ and V₂, so at least one of the vectors in the set is a linear combination of the others and set is linearly dependent.

Step-by-step explanation:

Given that;

If V₁ ....... V₄ are in R⁴ and V₃ = 2V₁ + V₂ then {V₁, V₂, V₃, V₄} is linearly dependent.

Lets {V₁, V₂, V₃, V₄} are linearly dependent

Then there exist a scalars C₁, C₂, C₃, C₄

So that C₁V₁ + C₂V₂ + C₃V₃ + C₄V₄ = 0

where at least one of the Ci ≠ 0.

Take C₃ ≠ 0 then we have V₃ = (C₁V₁ + C₂V₂ + C₄V₄) / C₃

V₃ is a linear combination of V₁, V₂ and V₄}

that is

Given V₃ = 2V₁ + V₂

⇒ 2V₁ + V₂ - V₃ = 0

⇒ 2V₁ + V₂ + V₃ + 0V₃ = 0

Here, C₁ = 1, C₂ = 1, C₃ = -1 and C₄ = 0

So that {V₁, V₂, V₃, V₄} is linearly dependent.

therefore option B id the right answer.

- True. The vector V₃ is a linear combination of V₁ and V₂, so at least one of the vectors in the set is a linear combination of the others and set is linearly dependent.

4 0

3 years ago

What’s the answer to this pls?

Andrews [41]

Answer:

(0, 1 x 5)

A. (0, 5) I think

Step-by-step explanation:

7 0

3 years ago