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aliina [53]
4 years ago
12

Which type of graph would allow us to quickly see how many students between 100 and 200 students were treated?

Mathematics
2 answers:
ira [324]4 years ago
8 0
I am thinking about a bar graph
Volgvan4 years ago
4 0
I think it might be a bar graph
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HELP PLEASE DUE IN 3 MINUTES
Allushta [10]

Answer:

the last answer... i hope this helps

Step-by-step explanation:

6 0
3 years ago
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In a journey of 450km a person complete its 150km in 3hours.Then he increases his speed by 20%.How long time does it take to com
earnstyle [38]

Answer:

450 km

150/3=50km/hr

50+20%

1/5*50=10

50+10=60

60km/hr

450-150=300

300/60=5

5 hours

8 0
3 years ago
The ratios in an equivalent ratio table are 3:12, 4:16, and 5:20. If the first number in the ratio is 10, what is the second num
nekit [7.7K]

Answer:

I believe the answer would be 10/40. First, I simplified all of the given rations. You do this by finding the two numbers greatest common factor. For example, 3/12, 3 goes into 3 once and 3 goes into 12 four times. So that ratio would be 1/4. If you continue the pattern you would get 1/4 for all of them. Therefore, 10/40 would be correct since it's ratio would also be 1/4.

Step-by-step explanation:

4 0
4 years ago
How do you work this problem out <br> Y+1/2=7/10
ch4aika [34]
Y= 1/5, this is because 1/2 is 5/10 and 1/5 is 2/10, therefore 5/10 + 2/10= 7/10
4 0
4 years ago
A fair coin is flipped twelve times. What is the probability of the coin landing tails up exactly nine times?
seraphim [82]

Answer:

P\left(E\right)=\frac{55}{1024}

Step-by-step explanation:

Given that a fair coin is flipped twelve times.

It means the number of possible sequences of heads and tails would be:

2¹² = 4096

We can determine the number of ways that such a sequence could contain exactly 9 tails is the number of ways of choosing 9 out of 12, using the formula

nCr=\frac{n!}{r!\left(n-r\right)!}

Plug in n = 12 and r = 9

       =\frac{12!}{9!\left(12-9\right)!}

       =\frac{12!}{9!\cdot \:3!}

       =\frac{12\cdot \:11\cdot \:10}{3!}            ∵ \frac{12!}{9!}=12\cdot \:11\cdot \:10

       =\frac{1320}{6}                   ∵ 3!\:=\:3\times 2\times 1=6

       =220

Thus, the probability will be:

P\left(E\right)=\frac{n\left(E\right)}{n\left(S\right)}

         =\frac{220}{4096}

         =\frac{55}{1024}

Thus, the probability of the coin landing tails up exactly nine times will be:

P\left(E\right)=\frac{55}{1024}

4 0
3 years ago
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