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tatuchka [14]
3 years ago
7

Anne is painting her house light blue. To make the color she wants, she must add 1/4 cans of white paint to every 1/2 cans of bl

ue paint. How many cans of white paint will she need to mix with 6 cans of blue?
Mathematics
2 answers:
Leviafan [203]3 years ago
8 0

Answer:she would require 3 cans of white paint to mix 6 cans of blue paint.

Step-by-step explanation:

To make the color she wants, she must add 1/4 cans of white paint to every 1/2 cans of blue paint. This means that the number of cans of white paint that she must add to 1 cup of blue paint would be 1/2.

Therefore, the number of cans of white paint that would be used to mix 6 cans of blue paint would be

6 × 1/2 = 3

yanalaym [24]3 years ago
5 0

Answer:

3 cans of white paint

Step-by-step explanation:

.25white     xwhite

_______=_______

.50blue        6blue

cross multiply .50x =1.5

divide by .50

and x = 3

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The answer to your question is 11
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3 years ago
Olivia is fixing her bicycle. She starts fixing it at 9:34 am and finishes at 1 pm. How much
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3 hours 26 minutes

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8 0
3 years ago
-2 1/6+(-2/3) please help me I really need help thanks
Charra [1.4K]

Answer: Your answer is -2 5/6

Step-by-step explanation:

Just convert the -2/3 to sixths. To do this, you multiply the denominator and numerator by 2 to make it equivalent to -2 1/6's denomenator (6). 2 times -2 is -4 and 3 times -2 is -6. This means -2/3 is equal to -4/6. As a result -2 1/6 - 4/6 is -2 5/6.

4 0
3 years ago
A visitor makes a list of 11 sights he’d like to see. He is determined to visit at least 8 of these. How many possible choices d
Cerrena [4.2K]

Using the combination formula, it is found that he has 232 choices.

The order in which the sights are seen is not important, hence the <em>combination formula </em>is used to solve this question.

<h3>What is the combination formula?</h3>

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by:

C_{n,x} = \frac{n!}{x!(n-x)!}

In this problem, the choices are 8, 9, 10 or 11 sights from a set of 11, hence:

T = C_{11,8} + C_{11,9} + C_{11,10} + C_{11,11} = \frac{11!}{3!8!} + \frac{11!}{2!9!} + \frac{11!}{10!1!} + \frac{11!}{0!11!} = 232

He has 232 choices.

You can learn more about the combination formula at brainly.com/question/25821700

4 0
2 years ago
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