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bixtya [17]
4 years ago
12

A coffee mixture has beans that sell for $1.35 per pound and beans that sell for $1.05 per pound. If 120 pounds of beans create

a mixture worth $1.15 per pound, how many pounds of each bean is used?
Mathematics
2 answers:
xxTIMURxx [149]4 years ago
5 0

Answer:

<u>40 lb of $1.35/lb; 80 lb of $1.05/lb</u>

insens350 [35]4 years ago
3 0
Let e be the amount of 1.35 beans and c be the amount of 1.05 beans...

(1.35e+1.05c)/120=1.15  we know e+c=120, so e=120-c making the equation:

(1.35(120-c)+1.05c)/120=1.15

(162-1.35c+1.05c)/120=1.15

162-0.3c=138

-0.3c=-24

c=80, and since e=120-c, e=40 so:

80 lb of the $1.05 beans are mixed with 40 lb of the $1.35 beans to produce a 120 lb mixture worth $1.15 per pound.
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Step-by-step walkthrough:

a.

Well a standard half-life equation looks like this.

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This is easy now that we have already made the function. Here we just reuse it, but plug in 2.8 days.

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