The <u>camera, projector</u>, invented by the Lumiere brothers in Paris included a <u>phonograph</u>.
- camera, projector, phonograph
<u>Explanation:</u>
Lumiere brothers, French designers and pioneer producers of photographic gear who formulated the early movie camera and projector called the Cinématographe. A cinematograph is a movie film camera, which likewise fills in as a film projector and printer.
The key development at the core of the Cinématographe was the instrument through which film was moved through the camera. It shows moving pictures on a screen. Which goes rapidly enough, an image replaces another too rapidly for the eye to see the change, along these lines shaping a moving picture.
It is a class C address. Class C covers all addresses in the range 192.0.0.0 to 223.0.0.0. The /24 represents the number of network bits in the address so we can work out that the subnet mask of this address would be 255.255.255.0.
Is there pictures or anything esle to read in order to figure out the answer
JAVA programming was employed...
What we have so far:
* Two 2x3 (2 rows and 3 columns) arrays. x1[i][j] (first 2x3 array) and x2[i][j] (second 2x3 array) .
* Let i = row and j = coulumn.
* A boolean vaiable, x1rules
Solution:
for(int i=0; i<2; i++)
{
for(int j=0; j<3; j++)
{
x1[i][j] = num.nextInt();
}
}// End of Array 1, x1.
for(int i=0; i<2; i++)
{
for(int j=0; j<3; j++)
{
x2[i][j] = num.nextInt();
}
}//End of Array 2, x2
This should check if all the elements in x1 is greater than x2:
x1rules = false;
if(x1[0][0]>x2[0][0] && x1[0][1]>x2[0][1] && x1[0][2]>x2[0][2] && x1[1][0]>x2[1][0] && x1[1][1]>x2[1][1] && x1[1][2]>x2[1][2])
{
x1rules = true;
system.out.print(x1rules);
}
else
{
system.out.print(x1rules);
}//Conditional Statement
The word you are looking for is active.
