Answer:
s(r(2)) = 6
Step-by-step explanation:
You would first solve for r(2). You then input r(2) which equals -2 into s(r(2)).
r(x)= -2x + 2
r(2)= -2(2) + 2
r(2)= -4 +2
r(2)= -2
s(x)=x² + 2
s(r(2)) = (-2)² +2
s(r(2)) = 6
Answer:
Step-by-step Explanation:
==>Given:
Dimensions of a rectangular prism are expressed as follow:
Volume (V) = 15x² + x + 2
Height (h) = x²
==>Required:
Expression of the Base area (B)
==>Solution:
Volume (V) = Base (B) × Height (h)
15x² + x + 2 = B × x²
Divide both sides by x²
![\frac{15x² + x + 2}{x²} = B[tex]Base (B) = /frac{15x² + 1 + 2}{x}](https://tex.z-dn.net/?f=%5Cfrac%7B15x%C2%B2%20%2B%20x%20%2B%202%7D%7Bx%C2%B2%7D%20%3D%20B%3C%2Fp%3E%3Cp%3E%5Btex%5DBase%20%28B%29%20%3D%20%2Ffrac%7B15x%C2%B2%20%2B%201%20%2B%202%7D%7Bx%7D)
You have the right idea but the endpoint is at the wrong location. Instead, the green dot should go at -1. The shading is to the right. We use a closed filled in circle here (instead of an open hole) to tell the reader "include the endpoint". So -1 is part of the solution set.
In short, the graph consists of a closed filled in circle at -1 with shading to the right. This visually describes all values that are larger than -1, or equal to -1.
