Given
in ∆ABC
AB = 5cm
BC = 6 cm
AC = 7 cm
now,
as we have to make ∆PQR inside it
than, possibly ∆PQR's sides length is,
PQ = ½ of CB (according to mid point theorem)
→ CB = 6cm → 6/2 → 3cm
PQ = 3cm
QR = ½ of AC
→ AC/2 = 7/2 = 3.5 cm
RP = ½ of AB
→ AB/2 = 5/2 = 2.5cm
therefore, length of
PQ = 3cm
QR = 3.5 cm
PR = 2.5 cm
Hope this answer helps you dear!
Conditional Probability
Given two events A and B (not excluding), the probability that A occurs given that B has occurred is called a <em>conditional probability</em> and is calculated as:
Where P(A∩B) is the probability that A and B occur simultaneously and P(B) is the probability that B occurs.
Now with the given data, we must find the values of the required probabilities.
30% of the students play a sport (S), this means that:
70% of the students don't play a sport (NS).
65% of the students have a job.
Note that there could be students who both play sports and have a job.
Of the 30% of the students who play a sport, 50% have a job. This means that:
15% of the students play a sport and don't have a job
15% of the students play a sport AND have a job
65% - 15% = 50% of the students have a job and don't play a sport
That last number is the numerator of the equation given above:
P(A∩B) = 0.5
The event B corresponds to students that don't play a sport (NS), thus:
P(B) = 0.7
Thus we have:
The required probability is 5/7 or 0.7143