I love military time its 1:45 am
You have shared the situation (problem), except for the directions: What are you supposed to do here? I can only make a educated guesses. See below:
Note that if <span>ax^2+bx+5=0 then it appears that c = 5 (a rational number).
Note that for simplicity's sake, we need to assume that the "two distinct zeros" are real numbers, not imaginary or complex numbers. If this is the case, then the discriminant, b^2 - 4(a)(c), must be positive. Since c = 5,
b^2 - 4(a)(5) > 0, or b^2 - 20a > 0.
Note that if the quadratic has two distinct zeros, which we'll call "d" and "e," then
(x-d) and (x-e) are factors of ax^2 + bx + 5 = 0, and that because of this fact,
- b plus sqrt( b^2 - 20a )
d = ------------------------------------
2a
and
</span> - b minus sqrt( b^2 - 20a )
e = ------------------------------------
2a
Some (or perhaps all) of these facts may help us find the values of "a" and "b." Before going into that, however, I'm asking you to share the rest of the problem statement. What, specificallyi, were you asked to do here?
la neta lo a mirado pero se me olvido if I'm right I think it' c
Answer:
Mmm
Step-by-step explanation:
wait I tell the answer
Answer:
Since there is a 50-50 chance of a person at the party choosing a gift card, and since there can only be 1 of 2 outcomes, we can assume that there will either be more people choosing a gift card than not, or there will be more people not choosing a gift card than are. So, that means that there would be 23 people (more or less) choosing a gift card and 22 people (more or less) not choosing a gift card or vice-versa.