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3 years ago

5yr is how many days

2 answers:

ivann1987 [24]3 years ago

8 0

Well there are 365 days in one year.
So we need to multiply that by 5.

365x5= 1,825

In five years one thousand- eight hundred and twenty five days will have passed.

Hope this helps!
~Brooke❤️

Karolina [17]3 years ago

6 0

There are 1,826 days in 5 yr. In relation to the leap year, there are 1826.25 days in 5 yrs. That is because there are really 365.25 days in a year (making every four years a leap year). So, when you multiply 365.25 by 5, you get 1826.25.

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Dak Prescott sucks<br> period <br> i dare you argue

Alexxx [7]

and btw go easy on his injury cowboys! till i die

Step-by-step explanation: my reasons:

The kind of dreams where you wake up and can’t stop smiling.

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3 years ago

Points A and B are on the different sides of a line 1, the distance between point A and the line lis 10 in, the distance between

givi [52]

Answer: Distance between O and the line 1 is 3 inches.

Explanation:

Since we have given that

Distance between point A and the line 1 = 10 inches

Distance between point B and the line 1 = 4 inches

Total length of segment AB is given by

$10+4=14\ inches$

Since O is midpoint of the line segment AB.

so, AO is given by

$\frac{14}{2}=7\ in.$

Now, Distance between O and the line 1 is given by

$10-7=3\ in.$

Hence, Distance between O and the line 1 is 3 inches.

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3 years ago

There are two college entrance exams that are often taken by students, Exam A and Exam B. The composite score on Exam A is appro

elena55 [62]

Answer:

B.The score on Exam A is better, because the percentile for the Exam A score is higher.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

Two exams. The exam that you did score better is the one in which you had a higher zscore.

The composite score on Exam A is approximately normally distributed with mean 20.1 and standard deviation 5.1.

This means that $\mu = 20.1, \sigma = 5.1$ .