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2 years ago

Where does the money come from that is used to pay taxes?

Mathematics

2 answers:

san4es73 [151]2 years ago

5 0

Answer:

Your correct answer is going to be the third option

Step-by-step explanation:

tensa zangetsu [6.8K]2 years ago

5 0

Answer:

sales tax

Step-by-step explanation:

I know because I'm smart

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Need help with this

Mkey [24]

1. is D number 2 is A

3 0

2 years ago

Find the value of x and y

vova2212 [387]

let's first off take a look at the tickmarks, three side tickmarks, so all those 3 sides are equal, all have a length of y - 25, so is an equilateral triangle.

there are two angle tickmarks, meaning those two angles are equal, wait a second! if those two angles are equal, that means is an isosceles triangle.

now, in an equilateral triangle, all sides are equal, but also all angles are equal, since the sum of all interior angles is 180°, then each angle is really 60°.

let's notice that angle on the upper-left-corner, is a right-angle, but 60° are on the equilateral triangle, and so the remaining 30° must be on the isosceles triangle.

the isosceles triangle has then a vertex of 30°, and twin angles, the twin angles let's say are each a° so then

30° + a° + a° = 180°

30 + 2a = 180

2a = 150

a = 75° = y

now, let's recall, the isosceles triangle has twin angles but it also has twin sides, so the side "x" and the side with the tickmark are equal.

well, we know that y = 75, so the sides with the tickmark are then (75) - 25 = 50 = x.

5 0

2 years ago

2 points) Sometimes a change of variable can be used to convert a differential equation y′=f(t,y) into a separable equation. One

Stells [14]

$y'=(t+y)^2-1$

Substitute $u=t+y$ , so that $u'=y'$ , and

$u'=u^2-1$

which is separable as

$\dfrac{u'}{u^2-1}=1$

Integrate both sides with respect to $t$ . For the integral on the left, first split into partial fractions:

$\dfrac{u'}2\left(\frac1{u-1}-\frac1{u+1}\right)=1$

$\displaystyle\int\frac{u'}2\left(\frac1{u-1}-\frac1{u+1}\right)\,\mathrm dt=\int\mathrm dt$

$\dfrac12(\ln|u-1|-\ln|u+1|)=t+C$

Solve for $u$ :

$\dfrac12\ln\left|\dfrac{u-1}{u+1}\right|=t+C$

$\ln\left|1-\dfrac2{u+1}\right|=2t+C$

$1-\dfrac2{u+1}=e^{2t+C}=Ce^{2t}$

$\dfrac2{u+1}=1-Ce^{2t}$

$\dfrac{u+1}2=\dfrac1{1-Ce^{2t}}$

$u=\dfrac2{1-Ce^{2t}}-1$

Replace $u$ and solve for $y$ :

$t+y=\dfrac2{1-Ce^{2t}}-1$

$y=\dfrac2{1-Ce^{2t}}-1-t$

Now use the given initial condition to solve for $C$ :

$y(3)=4\implies4=\dfrac2{1-Ce^6}-1-3\implies C=\dfrac3{4e^6}$

so that the particular solution is

$y=\dfrac2{1-\frac34e^{2t-6}}-1-t=\boxed{\dfrac8{4-3e^{2t-6}}-1-t}$

3 0

2 years ago

P: 2,012

OleMash [197]

El volumen remanente entre la esfera y el cubo es igual a 30.4897 centímetros cúbicos.

<h3>¿Cuál es el volumen remanente entre una caja cúbica vacía y una pelota?</h3>

En esta pregunta debemos encontrar el volumen remanente entre el espacio de una caja cúbica y una esfera introducida en el elemento anterior. El volumen remanente es igual a sustraer el volumen de la pelota del volumen de la caja.

Primero, se calcula los volúmenes del cubo y la esfera mediante las ecuaciones geométricas correspondientes:

Cubo

V = l³

V = (4 cm)³

V = 64 cm³

Esfera

V' = (4π / 3) · R³

V' = (4π / 3) · (2 cm)³

V' ≈ 33.5103 cm³

Segundo, determinamos la diferencia de volumen entre los dos elementos:

V'' = V - V'

V'' = 64 cm³ - 33.5103 cm³

V'' = 30.4897 cm³

El volumen remanente entre la esfera y el cubo es igual a 30.4897 centímetros cúbicos.

Para aprender más sobre volúmenes: brainly.com/question/23940577

#SPJ1

3 0

1 year ago

Do alternate interior angles add to 180 degrees

Anna007 [38]

Yes, they can add up to 180 degrees. Say one angle is 65 degrees, and the other one is 115 degrees. That would equal to 180 degrees.
Hope this helps.

3 0

2 years ago

Read 2 more answers