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Umnica [9.8K]
3 years ago
13

A triangle can be formed with side lengths 4 in, 5 in, and 8 in. (5 points) False True

Mathematics
1 answer:
marin [14]3 years ago
6 0

Answer:

True

Step-by-step explanation:

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How much will have to deposit into an account that pays 5.25% simple interest today, in order to earn $345.45 interest in seven
Ann [662]

To earn $345.45 simple interest in 7 years, you have to invest $940.

<u>Step-by-step explanation:</u>

Step 1:

Given details are Simple Interest Rate (R) = 5.25%, Simple Interest (SI) = $345.45, Time (T) = 7 years

Step 2:

Use the above details to find principal using the formula for Simple Interest (SI) = PRT/100

⇒ 345.45 = (P × 5.25 × 7)/100

⇒ 34545 = 36.75 P

⇒ P = $940

3 0
3 years ago
which strategy do you prefer to use to multiply with multiples of 10: base ten blocks, a number line, or place value? Explain wh
ladessa [460]
Place value. when multiplying by 10 you are moving a decimal, having everything lined up like place value would save you a lot of time.
7 0
3 years ago
Read 2 more answers
A part of a line with endpoints on both ends is a(n):
patriot [66]

I believe it's a segment.

4 0
4 years ago
The escalator rises 25° from the ground and a vertical distance of 42 feet. How much horizontal distance does the escalator cove
zvonat [6]
Tangent (25) = opp / adj = 42 / horizontal distance
horizontal distance =  42 / tangent (25)
horizontal distance = 42 / 0.46631
horizontal distance = <span> <span> <span> 90.068838326435200 </span> </span> </span>
horizontal distance = 90.1 feet


5 0
3 years ago
Janet deposited $9,600 into an account that pays 4.4 interest, compounded daily. At the end of nine months, how much interest ha
neonofarm [45]

bearing in mind that 9 months is not even a year, but since there are 12 months in a year, then 9 months is really 9/12 years.


\bf ~~~~~~ \stackrel{\textit{daily}}{\textit{Continuously}} \textit{Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$9600\\ r=rate\to 4.4\%\to \frac{4.4}{100}\dotfill &0.044\\ t=years\to \frac{9}{12}\dotfill &\frac{3}{4} \end{cases} \\\\\\ A=9600e^{0.044\cdot \frac{3}{4}}\implies A=9600e^{0.033}\implies A\approx 9922.09 \\\\\\


\bf \stackrel{\textit{interest earned}}{9922.09-9600\implies 322.09}

5 0
3 years ago
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