All categories

2 years ago

Please help me out with this asap.

Mathematics

1 answer:

Maru [420]2 years ago

6 0

Answer:

a) 21

b) 3905.44236

c) 251.94689

d) 1763.62824

Step-by-step explanation:

a) 42÷2=21

b) 60x42=2520

$\pi$ r²=1385.44236

2520+1385.44236=3905.44236

c) 2x $\pi$ x21=131.94689+60+60=251.94689

d) 251.94689x7=1763.62824

You might be interested in

Write the formula that expresses the relationship described "c varies directly<br> as a"

olga55 [171]

Answer:

a+b+c

find b

then

add a+b+c

7 0

2 years ago

Write the first 4 terms of the sequence defined by the given rule f(n)=n2 -1

Softa [21]

Answer:

Step-by-step explanation:

Substitute n = 1, n = 2, n = 3 and n = 4 to the equation f(n) = n² - 1:

f(1) = 1² - 1 = 1 - 1 = 0

f(2) = 2² - 1 = 4 - 1 = 3

f(3) = 3² - 1 = 9 - 1 = 8

f(4) = 4² - 1 = 16 - 1 = 15

5 0

2 years ago

Which of the following has no effect on the monthly payment?

Ivahew [28]

where are the answer choices?

5 0

3 years ago

Differentiating a Logarithmic Function in Exercise, find the derivative of the function. See Examples 1, 2, 3, and 4.

adoni [48]

Answer: The required derivative is $\dfrac{8x^2+18x+9}{x(2x+3)^2}$

Step-by-step explanation:

Since we have given that

$y=\ln[x(2x+3)^2]$

Differentiating log function w.r.t. x, we get that

$\dfrac{dy}{dx}=\dfrac{1}{[x(2x+3)^2]}\times [x'(2x+3)^2+(2x+3)^2'x]\\\\\dfrac{dy}{dx}=\dfrac{1}{[x(2x+3)^2]}\times [(2x+3)^2+2x(2x+3)]\\\\\dfrac{dy}{dx}=\dfrac{4x^2+9+12x+4x^2+6x}{x(2x+3)^2}\\\\\dfrac{dy}{dx}=\dfrac{8x^2+18x+9}{x(2x+3)^2}$

Hence, the required derivative is $\dfrac{8x^2+18x+9}{x(2x+3)^2}$

3 0

2 years ago

∠AZB and ∠CZB are supplementary. The m∠AZB = 2x - 4 and m∠CZB = 8x + 4. What is the measure of each angle?

g100num [7]

The answer is A because when you add the angles to get they equal 180. Then just solve for x.

The drawing isn't to scale

7 0

3 years ago

Read 2 more answers

Please help me out with this asap.​

Please help me out with this asap.