Reasoning point F lies on EG and point M lies on EN. If F,E, and M are collinear, what must be true of these rays.

2 answers:

6 0

This means that all of the points are co-linear. This is because if EG is a segment that contains F, and EN is a segment that contains M, then there can be two different segments. However, for a point F on the first segment and a point M on a second segment be in the same line as an end point of one of the segments, the segments have to be co-linear. They overlap.

trasher [3.6K]3 years ago

6 0

Some options would have definitely helped in answering this question. i am answering this question based on my knowledge. <span>If F,E, and M are collinear, then EG and EN will form a line. I hope that this is the answer that you were looking for and the answer has actually come to your desired help.</span>

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The directrix of a parabola is x = 4. Its focus is (2,6) .

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Answer:

Step-by-step explanation:

If you plot the directrix and the focus, you can see that the focus is to the left of the directrix. Since a parabola ALWAYS wraps itself around the focus, our parabola opens sideways, to the left to be specific. The formula for the parabola that opens to the left is

$-(y-k)^2=4p(x-h)$

We will solve this for x at the end. The negative is out front because it opens to the left. If it opened to the right, it would be positive.

The vertex of a parabola is exactly halfway between the focus and the directrix, so our vertex coordinates h and k are (3, 6). P is defined as the distance between the vertex and the directrix, or the vertex and the focus. Since the vertex is directly between both the directrix and the focus, each distance is the same. P = 1. Filling in what we have now:

$-(y-6)^2=4(1)(x-3)$ which simplifies to