Question

Suppose the probability that it rains in the next two days 1/3 for tomorrow and 1/6"for the day after tomorrow. What is P(rain tomorrow, then rain the day after tomorrow)?
A.1/2
B.1/18
C.2/9
D.1/9

Answer 1

This events are separate , so the probability of both of which combined is the product of them.

Let P(A) rain tomorrow event
      P(B) rain after tomorrow event

P(A) = 1/3

P(B) = 1/6

P(A in B) = P(A) * P(B) = 1/3 * 1/6= 1/18   

Choice: (B)

Answer 2

Answer:

$\frac{1}{18}$

Step-by-step explanation:

Probability that it rains tomorrow P(A)=  $\frac{1}{3}$

Probability that it rains day after tomorrow P(B)= $\frac{1}{6}$

So, P(rain tomorrow, then rain the day after tomorrow)

$P(A) \times P(B)$

$\frac{1}{3} \times \frac{1}{6}$

$\frac{1}{18}$

Hence P(rain tomorrow, then rain the day after tomorrow) is $\frac{1}{18}$

So, Option B is correct.