Answer:
640
Step-by-step explanation:
you say 100% = 800
what about 80%(i get 80% after substracting 100% that's marked price - 20% discount)
then u say 80×800÷100
Answer:
51
1−2+3−4+5−.....+101
=(1+3+5+.....+101)−(2+4+6+.....+100)
=(1+3+5+.....+101)−2(1+2+3+.....+50)
=(51)
2
−2(
2
50(50+1)
)
=2601−2×1275
=2601−2550
=51
Answer:
Below in bold.
Step-by-step explanation:
Work in times to fill 1 pail:-
tap A takes 55/4 seconds
tap B takes 50/3 seconds
Let time to fill one pail be x when filling together, then:
3/50 + 4/55 = 1/x
165x + 200x = 55*50
x = 2750 /(365) = 7.5342 seconds
To fill 16 pails it takes 7.5342* 16
= 120.55 seconds
= 2 minutes 1 second to the nearest second..
Answer:
Equation to be solved: 2+3x=15.5
The solution we want is: 4.5 million
The solution for p is: p=4.5
Step-by-step explanation:
The problem says:
15.5 million is 2 million more than 3 times the population in 1950.
We can write this as an equation like this:
15.5 million = 2 million + 3(x million).
Each term contains the factor of million so if we divide both sides by a million the equation can actually be written as:
15.5 =2 + 3(x)
15.5 =2 + 3x
So the equation we need to solve is:
15.5=2+3x
We want to isolate 3x. To do this we need to subtract 2 on both sides:
15.5=2+3x
-2 -2
-----------------
13.5= 3x
Divide both sides by 3:
13.5/3 = 3x/3
Simplifying both sides gives:
4.5=x
So 4.5 million is the population in 1950's.
<u>Given:</u>
A larger circle consisting of two circles with radii of 4 cm and 8 cm each.
<u>To find:</u>
The area of the shaded region.
<u>Solution:</u>
The centers of the circles with radii 4 cm and 8 cm lie on the same line as the center of the larger circle.
So the diameter of the outer circle cm.
If the diameter is 24 cm, the radius is cm.
The area of the shaded region is obtained by subtracting the areas of the two inner circles from the outer circle.
The area of a circle
The area of the circle with radius 12 cm square cm.
The area of the circle with radius 8 cm square cm.
The area of the circle with radius 4 cm square cm.
The area of the shaded region square cm.
Rounding this off to the nearest tenth, we get the area of the shaded region as 201 square cm.