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Romashka-Z-Leto [24]
3 years ago
5

Please help thanks very much

Mathematics
1 answer:
olchik [2.2K]3 years ago
6 0
A)
sinA = 8√3 / 16 = √3 / 2

answer is B
√3 / 2

B) It's 30 60 90 right triangle 
so <B is 30

answer is A
m<B = 30
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How many perfect cubes are there between 2 to 200 ?<br> ANSWER fast
Mekhanik [1.2K]

Answer:

Three

Step-by-step explanation:

The perfect cubes between 2 to 200 are

{3}^{3}  = 27 \\  \\  {4}^{3}  = 64 \\  \\  {5}^{3}  = 125 \\

Hence, there are only three perfect cubes 27, 64 and 125 between 2 to 200.

3 0
3 years ago
An ostrich can run 174 feet in 3 seconds.
bonufazy [111]

Answer:

58 I think i'm wrong tho

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Let ABC be an isosceles triangle with AB = AC and ∠BAC=30°. Side AB and the median AD contain points Q and P respectively (point
Svet_ta [14]

Answer:

  15°

Step-by-step explanation:

Since P is on the median of ΔABC, it is equidistant from points B and C as well as from C and Q. Thus, points B, C, and Q all lie on a circle centered at P. (See the attached diagram.)

The base angles (B and C) of triangle ABC are (180° -30°)/2 = 75°. This means arc QC of the circle centered at P has measure 150°. The diameter of circle P that includes point Q is defined to intersect circle P at R.

Central angle RPC is the difference between arcs QR and QC, so is 180° -150° = 30°. Inscribed angle RQC has half that measure, so is 15°.  Angle PQC has the same measure as angle RQC, so is 15°.

Angle PQC is 15°.

5 0
3 years ago
So,some please help!
Leni [432]
4.6 is the correct answer. Hope I helped:)
5 0
2 years ago
Read 2 more answers
The population of a town has approximately doubled every 17 years since 1950. If the equation P=Po2k, where Po is the population
natka813 [3]

The population of a town has approximately doubled every 17 years since 1950.

the equation P=P_02^k where Po is the population of the town in 1950, is used to model the population, P, of the town t years after 1950.

When t=17 yrs

   P=2p_{0}      

for 1 year

The equation becomes

P = P_02^\frac{t}{17}                               -------------(1)

Our original equation is

P=P_02^k----------------------------------(2)

equating expression 1  and 2

P_02^\frac{t}{17}=P_{0}2^k

Cancelling P_{0}  from both sides  we get

2^\frac{t}{17}=2^{k}

t/17=k

⇒k=t/17 is the solution.






4 0
3 years ago
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