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Leni [432]
3 years ago
11

Which distance measures 7 units? A number line going from negative 8 to positive 8. A closed circle appears at negative 7 and is

labeled L. A closed circle appears at negative 1 and is labeled M. A closed circle appears at positive 2 and is labeled N. A closed circle appears at positive 6 and is labeled P. An orange arrow line is above the number line with an arrow pointing left passed negative 7 and right passed positive 6. It contains all points. the distance between points L and M the distance between points L and N the distance between points M and N the distance between points M and P
Mathematics
2 answers:
kramer3 years ago
6 0

Answer:

the distance between points M and P

Step-by-step explanation:

JUST TOOK THE TEST

wolverine [178]3 years ago
3 0

Answer:

m and p

Step-by-step explanation:

because im never wrong

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A page should have perimeter of 42 inches. The printing area within the page
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Overall  dimensions of the page in order to maximize the printing area is  page should be 11 inches wide and 10 inches long .

<u>Step-by-step explanation:</u>

We have , A page should have perimeter of 42 inches. The printing area within the page  would be determined by top and bottom margins of 1 inch from each side, and the  left and right margins of 1.5 inches from each side. let's assume  width of the page be x inches  and its length be y inches So,

Perimeter = 42 inches

⇒ 2(x+y) = 42\\x+y = 21\\y = 21-x

width of printed area = x-3  & length of printed area = y-2:

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area = (x-3)(y-2)\\area = (x-3)(21-x-2)\\area = (x-3)(19-x)\\area = -x^{2} + 22x -57

Let's find \frac{d(area)}{dx}:

\frac{d(area)}{dx} = \frac{d(-x^{2}+22x-57)}{dx} = -2x +22 , for area to be maximum \frac{d(area)}{dx}= 0

⇒ -2x+22 = 0\\2x =22\\x=11 inches

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y = 21-x\\y = 21-11\\y = 10 inches

∴ Overall  dimensions of the page in order to maximize the printing area is  page should be 11 inches wide and 10 inches long .

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