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Andrei [34K]
2 years ago
9

The United States has 12383 miles of a coastline. If .8% of the coastline is located in Georgia, then about how many miles of co

astlines are in Georgia?
Mathematics
1 answer:
In-s [12.5K]2 years ago
6 0
So you have to find 0.8% of 12383 to find the answer. You do this by first dividing 12383 by 1000 to get 0.1%, which is 1.2383. Then, you multiply 1.2383 by 8 to get 0.8%, which is 9.9064 miles, which is your answer. Hope this helped!
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Luisa had $29.90 in her piggy bank. She made $5.50 a week for 4 weeks by baby-sitting. Write a sequence to show how much money s
Temka [501]

Answer:Week 1:  $35.40

              Week 2: $40.90

              Week 3: $46.40

               Week 4: $51.90

Step-by-step explanation:

29.90 + 5.50(x) = y

replace x with 1, 2, 3, or 4 for each week.

4 0
3 years ago
Please help!! i will help you back!!
NeX [460]

Answer:

c = 50

Step-by-step explanation:

Using the Pythagorean Theorem:

Plug in the values of a = 14, and b = 48

a^{2} +b^{2} =c^{2}\\14^{2} +48^{2} =c^{2}  \\c^{2} = 2500\\c = \sqrt{2500} \\c = 50

7 0
3 years ago
Please Help!!!!!!
navik [9.2K]

Answer:

6 team members

Step-by-step explanation:

We know that 2 team members can solve 13 problems in an hour. So, all you have to do is find what 195÷13 is, and multiply that by 2.

195÷13= 315

15*2= 30

And we have our answer!

I hope this helps! If it did, it would mean a lot to me if you could mark me brainliest :D

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7 0
3 years ago
Read 2 more answers
Determine if the sequence below is arithmetic or geometric and determine the
Brrunno [24]
The sequence is arithmetic since the common difference that is equal
d=11-15=7-11=-4
a(n) = a1 +(n-1)d
a1=15
=
a(n) = 15+(n-1)-4
5 0
3 years ago
Construct the confidence interval for the population mean mu. c = 0.90​, x = 16.9​, s = 9.0​, and n = 45. A 90​% confidence inte
Georgia [21]

Answer:

The  90%  confidence interval for population mean is   14.7  <  \mu  <  19.1

Step-by-step explanation:

From the question we are told that

   The sample mean is  \= x  =  16.9

    The confidence level is  C  =  0.90

     The sample size is  n  =  45

     The standard deviation

Now given that the confidence level is  0.90 the  level of significance is mathematically evaluated as

       \alpha =  1-0.90

       \alpha  =  0.10

Next we obtain the critical value of  \frac{\alpha }{2}  from the standardized normal distribution table. The values is  Z_{\frac{\alpha }{2} } =  1.645

The  reason we are obtaining critical values for \frac{\alpha }{2}  instead of  that of  \alpha  is because \alpha  represents the area under the normal curve where the confidence level 1 - \alpha (90%)  did not cover which include both the left and right tail while \frac{\alpha }{2}  is just considering the area of one tail which is what we required calculate the margin of error

  Generally the margin of error is mathematically evaluated as

        MOE  =  Z_{\frac{\alpha }{2} } *  \frac{\sigma }{\sqrt{n} }

substituting values

         MOE  = 1.645*  \frac{ 9 }{\sqrt{45} }

         MOE  = 2.207

The  90%  confidence level interval is mathematically represented as

      \= x  -  MOE  <  \mu  <  \= x  +  MOE

substituting values

     16.9 -  2.207  <  \mu  <  16.9 +  2.207

    16.9 -  2.207  <  \mu  <  16.9 +  2.207

     14.7  <  \mu  <  19.1

         

3 0
3 years ago
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