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2 years ago

What is the solution to the equation 4x+16-x=22+6

Mathematics

1 answer:

riadik2000 [5.3K]2 years ago

7 0

Simplifying

4x + 16 + -1x = 22 + 6

Reorder the terms:

16 + 4x + -1x = 22 + 6

Combine like terms: 4x + -1x = 3x

16 + 3x = 22 + 6

Combine like terms: 22 + 6 = 28

16 + 3x = 28

Solving

16 + 3x = 28

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-16' to each side of the equation.

16 + -16 + 3x = 28 + -16

Combine like terms: 16 + -16 = 0

0 + 3x = 28 + -16

3x = 28 + -16

Combine like terms: 28 + -16 = 12

3x = 12

Divide each side by '3'.

x = 4

Simplifying

x = 4

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Company A
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3 years ago

Salina is 63 inches tall. approximately how tall is she in centimeters?

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3 years ago

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Step-by-step explanation:

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2 years ago

Find the area of a triangle whose vertices are (0,0), (4,2), (-1,2)

Yakvenalex [24]

Answer:

Therefore area of a triangle whose vertices are (0,0), (4,2), (-1,2) is

5 units².

Step-by-step explanation:

Given:

Let the vertices be,

point A( x₁ , y₁) ≡ ( 0 , 0)

point B( x₂ , y₂) ≡ (4 , 2)

point C(x₃ , y₃ ) ≡ (-1 , 2)

To Find:

Area of Triangle = ?

Solution:

If the Vertices A( x₁ , y₁), B( x₂ , y₂) and C(x₃ , y₃ ) then the Area of Triangle is given by

$\textrm{Area of Triangle}=\dfrac{1}{2}(x_{1}(y_{2}-y_{3})+x_{2}(y_{3}-y_{1})+x_{3}(y_{1}-y_{2}))$

Substituting the values we get

$\textrm{Area of Triangle}=\dfrac{1}{2}(0(2-2)+4(2-0)+(-1)(0-2))$

$\textrm{Area of Triangle}=\dfrac{1}{2}(0+8+2))=\dfrac{10}{2}=5\ units^{2}$

Therefore area of a triangle whose vertices are (0,0), (4,2), (-1,2) is

5 units².

7 0

2 years ago