Answer:
Therefore area of a triangle whose vertices are (0,0), (4,2), (-1,2) is
5 units².
Step-by-step explanation:
Given:
Let the vertices be,
point A( x₁ , y₁) ≡ ( 0 , 0)
point B( x₂ , y₂) ≡ (4 , 2)
point C(x₃ , y₃ ) ≡ (-1 , 2)
To Find:
Area of Triangle = ?
Solution:
If the Vertices A( x₁ , y₁), B( x₂ , y₂) and C(x₃ , y₃ ) then the Area of Triangle is given by

Substituting the values we get


Therefore area of a triangle whose vertices are (0,0), (4,2), (-1,2) is
5 units².