Answer:
6.25 % of area of Large triangle = area of smallest triangle
Step-by-step explanation:
Area of large triangle L = (1/2)*base*height
L = (1/2)*(44 m)* h
L = 22*h square m.
2nd equilateral triangle area: S =(1/2)*(22 m)*(0.5h)
S = 5.5*h sq. m.
3rd smallest equilateral triangle area : T = (1/2)*(11 m)*(0.25h)
T = 1.375*h sq. m
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Find percent P where T = P* L, 1.375*h = P * 22*h
P = 6.25% = 0.0625
Step-by-step explanation:
See attached image for proof
If the choices are the following:
The legs are congruent.
The base angles are congruent.
The bases are | |.
<span>The diagonals are congruent.
Then , to prove </span>ACD ≅ BDC by SSS I would use The base angles are congruent.
<span>This is sufficient to prove the triangles are congruent.</span>
