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NikAS [45]
2 years ago
11

What is 5(x -5) = x(14 -4)

Mathematics
1 answer:
Tju [1.3M]2 years ago
7 0
<span>5(x -5) = x(14 -4) =>5*x-5*5=x*10 => 5x-25=10x =>10x-5x=-25 =>5x=-25 => x= -25/5=-5</span>
Have a nice day!! ^^<span>
</span>
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Hi! 6 questions, find the slope of the line through the given points, ty! They should be practice questions
denis23 [38]

Answer:

3. undefined (vertical line)

4. 1

7. -4

8. 3

11. undefined (vertical line)

12. -1/3

Step-by-step explanation:

You can use the slope formula to calculate the slope which is (y2-y1)/(x2-x1)

3. (-4 - (-2)) /  (6-6)  denominator is 0 here so the slope is undefined (vertical line)

4. (7 - 1) / (-2 - (-4)) = 6 / 6 = 1

7. (1 - (-7)) / (2 - 4) = 8 / -2 = -4

8. (-1 - 5) / (0 -2 ) = -6 / -2 = 3

11. (3 - 0) / (-6 - (-6)) = 3 / 0 = undefined (vertical line

12. (2 - 3) / (-5 - (-2) = 1 / -3 = -1/3

7 0
1 year ago
Find the missing number.<br> 7 × <br> = 21
dalvyx [7]

Answer:

7x3=21

Step-by-step explanation:

pls mark Brainliest :)

3 0
3 years ago
Q plus 12 minus 2=????
Rashid [163]
Answer is: <span>Q+12-2 =<span> q+10</span></span>
4 0
3 years ago
I need all please help
RUDIKE [14]

Answer:

5) D

6) C

7) B

8) D

9) 109°

10) 83°

Step-by-step explanation:

5) In y=mx+b the slope is m. In perpendicular it'll be opposite, so the answer is D.

6) With the above knowledge about slope, the slope will be the same so it'll be C.

7) They are in the same position by different lines and will be corresponding aka B

8) These are adjacent angles because they are next to each other aka D

9) 180 - 71 = 109

10) They are correspodning so 83°

(slightly rushing so I hope this helped, have a nice day!)

6 0
3 years ago
The sum of the first two terms of an infinite GP is 6 and each term is 5 times the sum of the succeeding termsthen the second te
kozerog [31]

Answer:

\dfrac{6}{7}.

Step-by-step explanation:

It is given that the sum of first two terms of an infinite GP is 6.

nth term of a GP is

a_n=ar^{n-1}

a+ar=6     ...(1)

Each term is 5 times the sum of the succeeding terms.

a_n=5(a_{n+1}+a_{n+2}+...+\infty)

ar^{n-1}=5(ar^n+ar^{n+1}+...+\infty)

ar^{n-1}=5ar^n(1+r+r^2+...+\infty)

Divide both sides by a.

r^{n-1}=5r^n(\dfrac{1}{1-r})    [\text{Sum of infinite GP}=\dfrac{a}{1-r}]

\dfrac{r^n}{r}=\dfrac{5r^n}{1-r}

\dfrac{1}{r}=\dfrac{5}{1-r}

1-r=5r

1=6r

\dfrac{1}{6}=r

The common ratio is 1/6.

Put r=1/6 in (1).

a+a(\dfrac{1}{6})=6

6a+a=36

7a=36

a=\dfrac{36}{7}

Second term ar=\dfrac{36}{7}\times \dfrac{1}{6}=\dfrac{6}{7}

Therefore, the second term is \dfrac{6}{7}.

4 0
2 years ago
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