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3 years ago

Find the product. y4 · y6

Mathematics

2 answers:

Otrada [13]3 years ago

7 0

The answer is $y^{4+6}$ = $y^{10}$

Lilit [14]3 years ago

7 0

The answer is y10 because they are common so al you have to do is multiply and bring the y down

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PLEASE HELP ASAP WILL MARK BRAINLIEST<br><br> Solve the quadratic equation <br> 18x^2 -153x -172 =0

Vika [28.1K]

Answer:

The answer is : x = 9.505 and x = -1.005

Step-by-step explanation:

To solve the quadratic equation use the formula :

$x=\frac{-b+\sqrt{b^{2}-4ac } }{2a}$

Where a is the coefficient of x² , b is the coefficient of x and c is the numerical term

∵ a = 18 , b = -153 and c = -172

∴ $x=\frac{-(-153)+\sqrt{(-153)^{2}-4(18)(-172) } }{2(18)}$

$x = \frac{18+\sqrt{35793} }{36} &x=\frac{18-\sqrt{35793} }{36}$

∴ x = 9.505 and x = -1.005

8 0

2 years ago

Three cell phones towers can be modeled by the points X(6,0), Y(8,4), and Z(3,9). Determine the location of another cell phone t

Marat540 [252]

Answer:

The location of the new cell phone tower is $(h,k) = (3,4)$ , and the equation of the circle is $x^{2}+y^{2} -6\cdot x - 8\cdot y = 0$ .

Step-by-step explanation:

The location of the cell phone tower coincides with the location of a circunference passing through the three cell phone towers. By Analytical Geometry, the equation of the circle is represented by the following general formula:

$x^{2} + y^{2}+A\cdot x + B\cdot y +C = 0$ (1)

Where:

$x$ - Independent variable.

$y$ - Dependent variable.

$A$ , $B$ , $C$ - Circunference constants.

Given the number of variable, we need the location of three distinct points:

$(x_{1},y_{1}) = (6,0)$

$36 +6\cdot A + C = 0$

$(x_{2},y_{2}) = (8,4)$

$80 + 8\cdot A + 4\cdot B + C = 0$

$(x_{3},y_{3}) = (3,9)$

$90 + 3\cdot A + 9\cdot B + C = 0$

Then, we have the following system of linear equations:

$6\cdot A + C = -36$ (2)

$8\cdot A +4\cdot B + C = -80$ (3)

$3\cdot A + 9\cdot B + C = -90$ (4)

The solution of this system is:

$A = -6$ , $B = -8$ , $C = 0$

By comparing the general form with the standard form of the equation of the circunference is:

$A = -2\cdot h$ (5)

$B = -2\cdot k$ (6)

$C = h^{2}+k^{2}-r^{2}$ (7)

Where:

$h$ , $k$ - Coordinates of the center of the circle.

$r$ - Radius of the circle.

If we know that $A = -6$ , $B = -8$ and $C = 0$ , then coordinates of the center of the circle and its radius are, respectively:

$h = -\frac{A}{2}$

$k = -\frac{B}{2}$

$r = \sqrt{h^{2}+k^{2}-C}$

$h = 3$ , $k = 4$ , $r = 5$

The location of the new cell phone tower is $(h,k) = (3,4)$ , and the equation of the circle is $x^{2}+y^{2} -6\cdot x - 8\cdot y = 0$ .

3 0

2 years ago

Make up a problem using the chart below 100 200 300 books toys notebook ?

torisob [31]

Safdsfghjklphuiyotrdtufchvjbkn;pp;lrsyketdgxvcb nmklj;pu8yutiyfgch bmhjkityfjhvyfug . =235678

3 0

2 years ago

Randy has 4 pennies, 3 nickels, and 3 dimes in his pocket. If he randomly chooses 2

zmey [24]

Answer: 3/10

Step-by-step explanation: by adding the number of coins up you get 10 coins, then minus how many pennies and nickels there are then it comes out with a proper fraction, no simlifying needed :)

7 0

3 years ago

How could you change the equation from Part B so it has infinitely many solutions? What would infinitely many solutions mean in

Andrews [41]

Answer:

We do not have the equation for the part B, so we can not aswer it correctly.

But i will give a general answer.

We could have infinite answers always when we have more variables than linear independent equations:

This is, if we have one variable, x, we can have infinite solutions if we have no equations (or equations with no restrictions for our variable)

So if we have an equation like:

x*4 = √16*x

you can see that both sides of the equation are exactly the same, so this equation actually does not have any value, and x could take infinite different values and the equation will remain true.

If we have two variables, x and y, we will have infinite solutions if we have only one equation:

y = a*x + b

We have infinite pairs (x, y)

4 0

3 years ago