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qaws [65]
3 years ago
13

Round this number to the nearest tenth 4.253

Mathematics
2 answers:
zhannawk [14.2K]3 years ago
6 0

hello.

the answer should be;


4.3

Savatey [412]3 years ago
3 0

The answer would be 4.300


Tip: If the number you are rounding is followed by 5, 6, 7, 8, or 9, round the number up and if the number you are rounding is followed by 0, 1, 2, 3, or 4, round the number down.


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Is this a reduction or enlargement?
Nesterboy [21]
Enlargement i think so
6 0
3 years ago
95i is a root of f(x)=x^2 +9025. find the other roots of f(x)
Alex_Xolod [135]

Answer:

Other root is -95i

Step-by-step explanation:

Here, Nature of roots of f(x) is imaginary roots.

Therefore, Roots are conjugate of each other.

Conjugate of x + yi is x - yi.

we get conjugate of 95i as -95i

Verification shows....

(x-95)(x+95i)=0

{x }^{2}  -  {95}^{2}  {i}^{2}  = 0 \\  {x }^{2}   + {95}^{2} = 0  \\ {x }^{2}   + 9025= 0   \\ f(x) = 0

this, roots are -95i and 95i

5 0
4 years ago
The hypotenuse of a right triangle is 34 inches. One leg of the triangle is 14 inches less than the other leg. In simplified for
Karolina [17]
You can use the equation

{(x + 14)}^{2}  +  {x}^{2}  =  {34}^{2}
to find the lenth of the legs

x = leg 1
x + 14 = leg 2
6 0
3 years ago
Read 2 more answers
What is 6+(-7)<br><br><br><br><br><br><br><br><br> Please <br> Please<br> Please<br> Please
kherson [118]
The answer would be -1
8 0
3 years ago
An estimated regression equation that was fit to estimate ductility in steel using its carbon content was found to be significan
AnnZ [28]

Answer:

At a level of 95%, it is expected that the interval [0.45; 11.59] contains the value of the ductility in steel when its carbon content is 0.5%.

Step-by-step explanation:

Hello!

Considering the dependent variable:

Y: Ductility in steel.

And the independent variable:

X: Carbon content of the steel.

The linear regression was estimated and a prediction interval was calculated.

The prediction interval is calculated to predict a value that the variable Y (response variable) can take for a given value of the variable X (predictor variable) in the definition range of the linear regression line. Symbolically [Y/X=x_{0}]

In this case 95% prediction interval for Y/X=0.5

At a level of 95%, it is expected that the interval [0.45; 11.59] contains the value of the ductility in steel when its carbon content is 0.5%.

I hope it helps!

6 0
3 years ago
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