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3 years ago

How do you write numbers without scientific notation

Mathematics

1 answer:

grigory [225]3 years ago

6 0

How do write whole numbers without scientific notation? can you elaborate on your question.

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Convert 25/8 into a mixed number

motikmotik

Changing improper fractions to mixed form or mixed numbers is a very simple thing. You just have to follow the following:
Then write Let us have 25/8. 
1. Divide the numerator (top number) by the denominator (number below the bar). Simply divide 25 by 8. 25 ÷ 8 = n
We can have 3 and 1 as a remainder. So, the answer will be 3 and 1/8. 

2. Write down the whole number answer.
Since we have 3 as the whole number answer, write it down. And; 

3. Write down any remainder above the denominator, like this: 3 and 1 (remainder) over 8 (denominator of the given improper fraction). That is, 3 1/8

3 0

3 years ago

Combine the like terms to create an equivalent expression: r+(−5r)

nevsk [136]

Answer:

-4r

Step-by-step explanation:

Since r and -5r both have the same variable, we can combine them

r-5r = -4r

r+(−5r) = -4r

8 0

2 years ago

What expression is equivalent to 4x-5-6x+7?

lesantik [10]

Answer:

-2x + 2

Step-by-step explanation:

you didn't post choices but combining like terms you get

-2x + 2

4 0

2 years ago

Read 2 more answers

I need to know the answer to the second one.

Debora [2.8K]

Travis got 43 dollars

Robin collected 35 percent more so we can model this with

Travis + (Travis x .35)

43 + 15.05 =58.05

Jessica colelcted 20 percent less so

Travis - (Travis x .20)

43 - 8.6 = 34.3

34.4 + 58.05 + 43 = 135.45

C is the closest

7 0

3 years ago

Read 2 more answers

How do I solve for x

Alchen [17]

Greetings!

To find the length of any side of a right triangle, you can use the Pythagorean Thereom. It states that the squares of two sides are equal to the square of the hypotenuse:
$a^2+b^2=c^2$

Input the information from the diagram into the formula:
$(x)^2+(x+7)^2=(13)^2$

Expand each term:
$(x)^2+(x+7)^2=(13)^2$

$x^2+((x+7)(x+7))=169$

$x^2+(x(x+7)+7(x+7))=169$

$x^2+x^2+7x+7x+49=169$

Combine like terms:
$2x^2+14x+49=169$

Add -169 to both sides:
$(2x^2+14x+49)+(-169)=(169)+(-169)$

$2x^2+14x-120=0$

Factor out the Common Term (2):
$2(x^2+7x-60)=0$

Factor the Complex Trinomial:
$2(x^2-5x+12x-60)=0$

$2(x(x-5)+12(x-5))=0$

$2(x-5)(x+12)=0$

Set Factors to equal 0:
$x-5=0$

$x=5$

or

$x+12=0$

$x=-12$

However, since we are solving for the side length, the only possible answer is 5 (a shape can't have a side with a negative length.)

The Solution Is:
$\boxed{x=5}$

I hope this helped!
-Benjamin

6 0

2 years ago