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scoray [572]
3 years ago
9

How do you write numbers without scientific notation

Mathematics
1 answer:
grigory [225]3 years ago
6 0
How do write whole numbers without scientific notation? can you elaborate on your question.
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I don’t know how to do this can someone please help
bezimeni [28]
The polynomial is subtracted using the distributive property.
.. (16k^3 -3v^4) -(-9k^3 +6v^4)
.. = 16k^3 -3v^4 +9k^3 -6v^4
.. = (16 +9)k^3 +(-3 -6)v^4
.. = 25k^3 -9v^4

"Invert" means different things in different contexts. Here we suppose it means you simply want the reciprocal of this difference:

\frac{1}{25k^{3} -9v^{4}}
8 0
3 years ago
A solid object is dropped into a pond with a temperature of 20 degrees Celsius. The function f(t)=Ce(−kt)+20 represents the situ
LenaWriter [7]

Answer:

The initial temperature of the object was 37.6 degrees Celsius

The initial temperature of the object was 37.6 (without units)

Step-by-step explanation:

we have

f(t)=Ce^{(-kt)} +20

where

f(t) represent the temperature of the object in degree Celsius

t is the time in minutes

<em>Find the value of the constant C</em>

we have the ordered pair (4,35)

substitute in the equation and solve for C

35=Ce^{(-0.0399*4)} +20

Ce^{(-0.0399*4)}=15

C=15/e^{(-0.0399*4)}

C=17.6

Find the initial value of the object

we know that

The initial temperature is the value of f(t) when the value of t is equal to zero

so

For t=0

f(0)=(17.6)e^{(-k*0)} +20

f(0)=17.6 +20

f(0)=37.6\ degrees\ Celsius

therefore

The initial temperature of the object was 37.6 degrees Celsius

The initial temperature of the object was 37.6 (without units)

3 0
3 years ago
What is the product (-6a^3b+2ab^2)(5a^2-2ab^2-b)
Musya8 [376]

-30a^5*b+12a^4b^2+6a^3b^2+10a^3b^2-4a^2b^3-2ab^3

7 0
4 years ago
Read 2 more answers
N*7=7n
Anettt [7]

Answer:

C

Step-by-step explanation:

law of communicative multiplication

3 0
3 years ago
Read 2 more answers
Please help i’m doing trying to do my gf work please i’ll give you brainliest
otez555 [7]

Answer:

t = 5 seconds h = 128 feet

Step-by-step explanation:

The given equation of the object is :

h(t)=-16t^2+64t+80 .....1

When it hits the ground,

h(t) = 0

So,

-16t^2+64t+80=0\\\\t=-1\ s\ and\ t=5\ s

The object will hit the ground in 5 seconds.

Now, put t = 1 s in equation (1).

h(1)=-16(1)^2+64(1)+80\\\\h(t)=128\ ft

The object is at a height of 128 ft at 1 second.

7 0
3 years ago
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