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3 years ago

Ill give a brainlist ! :>

Mathematics

1 answer:

bekas [8.4K]3 years ago

7 0

Answer:

Answer is given above in the image 

Step-by-step explanation:

I hope this will help you 

 HAVE A NICE DAY!

THANKS FOR GIVING ME THE OPPORTUNITY TO ANSWER YOUR QUESTION. 

ANSWER IS (c+8)(c+3)

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Which graph shows a line with the slope of 3/2?

Mnenie [13.5K]

Answer:

Step-by-step explanation:

slope = Rise (y difference) / Run (x difference)

B, Rise = 3 run = 2 slope = 3/2

8 0

3 years ago

,,,,,,,,,,,,,,,,,i want the answer

marysya [2.9K]

Answer:

120 Degrees

Step-by-step explanation:

As the set up says the two angles (m<A and m<C) are the same so you would simply just divide 240 by 2 (240/2) to find your answer of 120.

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3 years ago

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Ainat [17]

The answer to your question is 22.875

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3 years ago

A container holds 24 pints of lemonade. How much is this in gallons?

krok68 [10]

Answer:

24 pints = 3 US liquid gallons

3 0

2 years ago

There are 3 islands A,B,C. Island B is east of island A, 8 miles away. Island C is northeast of A, 5 miles away and northwest of

Nostrana [21]

Answer:

The bearing needed to navigate from island B to island C is approximately 38.213º.

Step-by-step explanation:

The geometrical diagram representing the statement is introduced below as attachment, and from Trigonometry we determine that bearing needed to navigate from island B to C by the Cosine Law:

$AC^{2} = AB^{2}+BC^{2}-2\cdot AB\cdot BC\cdot \cos \theta$ (1)

Where:

$AC$ - The distance from A to C, measured in miles.

$AB$ - The distance from A to B, measured in miles.

$BC$ - The distance from B to C, measured in miles.

$\theta$ - Bearing from island B to island C, measured in sexagesimal degrees.

Then, we clear the bearing angle within the equation:

$AC^{2}-AB^{2}-BC^{2}=-2\cdot AB\cdot BC\cdot \cos \theta$

$\cos \theta = \frac{BC^{2}+AB^{2}-AC^{2}}{2\cdot AB\cdot BC}$

$\theta = \cos^{-1}\left(\frac{BC^{2}+AB^{2}-AC^{2}}{2\cdot AB\cdot BC} \right)$ (2)

If we know that $BC = 7\,mi$ , $AB = 8\,mi$ , $AC = 5\,mi$ , then the bearing from island B to island C:

$\theta = \cos^{-1}\left[\frac{(7\mi)^{2}+(8\,mi)^{2}-(5\,mi)^{2}}{2\cdot (8\,mi)\cdot (7\,mi)} \right]$

$\theta \approx 38.213^{\circ}$

The bearing needed to navigate from island B to island C is approximately 38.213º.

8 0

3 years ago