Answer:
Figure A
Step-by-step explanation:
Hope it helps.
The value of x is 7 because 8/24 = 1/3 so find 1/3 of 21
You need LCD or the least common denominator. For 4 over 8 and 2 over 8 have the same denominators except for 2 over 4. You need to ask yourself what times 4 equals to 8? 4 times 2 equals to 8, so multiply 4x2 for the denominator and for the numerator multiply 2x2. Whatever you do to the denominator you have to do the same thing to the numerator. You multiplied 4x2 for the denominator and 2x2 for the numerator and now your fraction is 4 over 8. Now add 4 over 8+ 4 over 8 which is 8 over 8 or 1. Now add 1+ 2 over 8 which is 1 2/8. If you simplify 1 2/8 it will become 1 1/4.
Hope that helped:D
Step-by-step explanation:
Confidence interval = mean ± margin of error
CI = μ ± ME
The mean is μ = 8.7.
Margin of error = critical value × standard error
ME = CV × SE
At 95% confidence and 9 degrees of freedom, CV = 2.262.
SE = s / √n
SE = 3.3 / √10
SE = 1.04
The margin of error is:
ME = 2.262 × 1.04
ME = 2.36
CI = 8.7 ± 2.36
CI = (6.34, 11.06)
Answer: 11113200
Step-by-step explanation:
We know that , the number of combination of choosing r things from n things is given by :-
![^nC_r=\dfrac{n!}{r!(n-r)!}](https://tex.z-dn.net/?f=%5EnC_r%3D%5Cdfrac%7Bn%21%7D%7Br%21%28n-r%29%21%7D)
Then , the number of ways to choose a dancing committee if it is to consist of 4 freshmen, 5 sophomores, 2 juniors, and 3 seniors :-
Then , the number of ways to choose a dancing committee if it is to consist of 4 freshmen, 5 sophomores, 2 juniors, and 3 seniors :-
Then , the number of ways to choose a dancing committee if it is to consist of 4 freshmen, 5 sophomores, 2 juniors, and 3 seniors :-
![^8C_4\times ^9C_5\times^9C_2\times^7C_3](https://tex.z-dn.net/?f=%5E8C_4%5Ctimes%20%5E9C_5%5Ctimes%5E9C_2%5Ctimes%5E7C_3)
![=\dfrac{8!}{(8-4)!4!}\times\dfrac{9!}{(9-5)!5!}\times\dfrac{9!}{(9-2)!2!}\times\dfrac{7!}{3!(7-3)!}\\\\ =\dfrac{8\times7\times6\times5\times4!}{4!4!}\times\dfrac{9\times8\times7\times6\times5!}{4!5!}\times\dfrac{9\times8\times7!}{7!2!}\times\dfrac{7\times6\times5\times4!}{3!4!}\\\\=11113200](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B8%21%7D%7B%288-4%29%214%21%7D%5Ctimes%5Cdfrac%7B9%21%7D%7B%289-5%29%215%21%7D%5Ctimes%5Cdfrac%7B9%21%7D%7B%289-2%29%212%21%7D%5Ctimes%5Cdfrac%7B7%21%7D%7B3%21%287-3%29%21%7D%5C%5C%5C%5C%20%3D%5Cdfrac%7B8%5Ctimes7%5Ctimes6%5Ctimes5%5Ctimes4%21%7D%7B4%214%21%7D%5Ctimes%5Cdfrac%7B9%5Ctimes8%5Ctimes7%5Ctimes6%5Ctimes5%21%7D%7B4%215%21%7D%5Ctimes%5Cdfrac%7B9%5Ctimes8%5Ctimes7%21%7D%7B7%212%21%7D%5Ctimes%5Cdfrac%7B7%5Ctimes6%5Ctimes5%5Ctimes4%21%7D%7B3%214%21%7D%5C%5C%5C%5C%3D11113200)
∴ The number of ways to choose a dancing committee if it is to consist of 4 freshmen, 5 sophomores, 2 juniors, and 3 seniors = 11113200