Identify the domain of the function.

Learning Task 1: Illustrate the following fractions on your notebook.

Marizza181 [45]

Answer:

The illustration is found in the attachment below.

Note: The correct order of the question is found below:

Learning Task 1: Illustrate the following fractions on your notebook.

a.)2/3 b.)7/9 c.)10/12 d.)8/12 e.)4/5 f.) 8/6 g.)9/4 h.) 28/10

Step-by-step explanation:

a) Draw a rectangle of sides 3 cm by 1 cm. Divide the rectangle into three equal parts. Shade two out of the three parts to give the fraction 2/3

b) Draw a rectangle of sides 9 cm by 1 cm. Divide the rectangle into nine equal parts. Shade seven out of the nine parts to give the fraction 7/9

c) Draw a rectangle of sides 12 cm by 1 cm. Divide the rectangle into twelve equal parts. Shade ten out of the twelve parts to give the fraction 10/12

d) Draw a rectangle of sides 12 cm by 1 cm. Divide the rectangle into twelve equal parts. Shade eight out of the twelve parts to give the fraction 8/12

e) Draw a rectangle of sides 5 cm by 1 cm. Divide the rectangle into five equal parts. Shade four out of the five parts to give the fraction 4/5

f) Draw two rectangle of sides 6 cm by 1 cm. Divide the rectangles into six equal parts each. Shade all the six parts of the first rectangle completely. Then, shade two out of the six parts of the second rectangle to give the fraction 8/6

g) Draw three rectangles of side 4 cm by 1 cm. Divide each of the three rectangles into four parts each. Shade completely the four parts of the first and second rectangle. Then, shade one part out of the four parts of the third rectangle to give the fraction 9/4

h) Draw three rectangles of side 10 cm by 1 cm. Divide each of the three rectangles into ten parts each. Shade completely the ten parts of the first and second rectangle. Then, shade eight parts out of the ten parts of the third rectangle to give the fraction 28/10

6 0

3 years ago

Velma needs to crate 59 watermelons. If she can fit 7 watermelons in each crate, how many crates does she need?

Mademuasel [1]

Answer:

The answer would be nine

Explanation:

59 divided by 7 is 8 with 3 remaning but all must be included so you have anothr crate for the remaining the and sice 8+1=9. Velma needs 9 crates. Hope this Helps!!

5 0

3 years ago

Five individuals from an animal population thought to be near extinction in a certain region have been caught, tagged, and relea

Talja [164]

Answer:

a) For this case the random variable X follows a hypergometric distribution.

b) $E(X)= n\frac{M}{N}=10 \frac{5}{25}=2$

$Var(X)=n \frac{M}{N}\frac{N-M}{N}\frac{N-n}{N-1}=10\frac{5}{25}\frac{25-5}{25}\frac{25-10}{25-1}=1$

c) $P(X=0)= \frac{(5C0)(25-5 C 10-0)}{25C10}=\frac{1*184756}{3268760}=0.0565$

d) $P(X=5)= \frac{(5C5)(25-5 C 10-5)}{25C10}=\frac{1*15504}{3268760}=0.00474$

Step-by-step explanation:

The hypergometric distribution is a discrete probability distribution that its useful when we have more than two distinguishable groups in a sample and the probability mass function is given by:

$P(X=k)= \frac{(MCk)(N-M C n-k)}{NCn}$

Where N is the population size, M is the number of success states in the population, n is the number of draws, k is the number of observed successes

The expected value and variance for this distribution are given by:

$E(X)= n\frac{M}{N}$

$Var(X)=n \frac{M}{N}\frac{N-M}{N}\frac{N-n}{N-1}$

a. What is the distribution of X?

For this case the random variable X follows a hypergometric distribution.

b. Compute the values for E(X) and Var(X)

For this case n=10, M=5, N=25, so then we can replace into the formulas like this:

$E(X)= n\frac{M}{N}=10 \frac{5}{25}=2$

$Var(X)=n \frac{M}{N}\frac{N-M}{N}\frac{N-n}{N-1}=10\frac{5}{25}\frac{25-5}{25}\frac{25-10}{25-1}=1$

c. What is the probability that none of the animals in the second sample are tagged?

So for this case we want this probability:

$P(X=0)= \frac{(5C0)(25-5 C 10-0)}{25C10}=\frac{1*184756}{3268760}=0.0565$

d. What is the probability that all of the animals in the second sample are tagged?

So for this case we want this probability:

$P(X=5)= \frac{(5C5)(25-5 C 10-5)}{25C10}=\frac{1*15504}{3268760}=0.00474$

4 0

3 years ago

What is 34×60 Brainliest Answer Wins

ANEK [815]

Answer:

2040

Step-by-step explanation:

34x60=2040

6 0

3 years ago

Read 2 more answers

Given the following equation where A = Area of a rectangle and w = width of the rectangle, what value of 'w' would maximize the

Papessa [141]

Answer:

the second option : w should be 25 units

Step-by-step explanation:

the area of the rectangle is length×width = L×W

the perimeter of a rectangle = 2L + 2W

now, we know that the perimeter is 100 units.

and we have to find the best length of W, that will then define L (to keep the 100 units of perimeter) and maximizes the area of the rectangle.

in other words, what is the maximum area of a rectangle with perimeter of 100 (and what are the corresponding side lengths)?

now, w = 625 is impossible. that side alone would be bigger than the whole perimeter.

W = 0 would render the whole rectangle to a flat line with L = 50 because of

100 = 2L + 2W = 2L + 0 = 2L

L = 50

and A = L×W = 50×0 = 0

an area of 0 is for sure not the largest possible area.

w = 50 would cause L = 0

100 = 2L + 2W = 2L + 2×50 = 2L + 100

0 = 2L

L = 0

and with L = 0 the same thing happens as with W = 0 : a flat line with 0 area.

so, the only remaining useful answer is W = 25

100 = 2L + 2W = 2L + 2×25 = 2L + 50

50 = 2L

L = 25

A = L×W = 25×25 = 625 units²

and indeed, the maximum area for a given perimeter is achieved by arranging the sides to create a square.

8 0

3 years ago