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sattari [20]
3 years ago
13

Radium-226 is a metal with a half-life of 1600 years. If you start with 1 kilogram of radium-226, how much will remain after 20,

000 years?
Mathematics
1 answer:
erica [24]3 years ago
6 0
Ending Amount = Beginning Amount / 2^n 
where 'n' = # of half lives
n = 20,000 / 1,600 = 12.5 half-lives

Ending Amount = 1 kg / 2^12.5
Ending Amount = 1 kg / <span> <span> <span> 5,792.6
</span></span></span>Ending Amount = <span> <span> <span> 0.00017263 kilograms = </span></span></span><span>0.17263 grams


</span>
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Thepotemich [5.8K]

We want to subtract 8x + 3 from -2x+5. We can create an expression to represent this.

-2x + 5 - (8x + 3).


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3 0
3 years ago
Divide the following quantiles in the given ratio £100 1:3 £80 3:5 £250 2:3:5
goblinko [34]

Answer:

Step-by-step explanation:

a.

£100

1:3

1+3=4

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=£25

3/4×£100

=£75

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£80

3:5

3+5=8

3/8×£80

=£30

5/8×£80

=£50

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6 0
3 years ago
write a system of linear equations that has only one solution. solve the system of equations in two ways.
Iteru [2.4K]
X + 5y = 1 . . . . (1)
8x - 2y = 3 . . . .(2)
Solution 1.
From (1), x = 1 - 5y
substituting for x in (2), we have:
8(1 - 5y) - 2y = 3
8 - 40y - 2y = 3
8 - 42y = 3
42y = 5
y = 5/42
x = 1 - 5(5/42) = 1 - 25/42 = 17/42.

Solution 2.
Multiply (1) by 8, to get:
8x + 40y = 8 . . . . . (3)
(3) - (2) = 40y - (-2y) = 8 - 3
42y = 5
y = 5/42
substitute for y into (3), to get:
8x + 40(5/42) = 8
8x + 100/21 = 8
8x = 8 - 100/21 = 68/21
x = (68/21)/8 = 17/42
7 0
3 years ago
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