if Dakota earned $15.75 in interest in account A and $28.00 in interest in account B after 21 months. if the simple interest rat
e is for 3.0% for account A and 4.9% for account B, which account had the greater principal? Explain.
1 answer:
keeping in mind that 21 months is more than a year, since there are 12 months in a year, then 21 months is really 21/12 years.


so, clearly, you can see who's greater.
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