Given that
z₁ = 15 (cos(90°) + i sin(90°))
z₂ = 3 (cos(10°) + i sin(80°))
we get the quotient z₁/z₂ by dividing the moduli and subtracting the arguments:
z₁/z₂ = 15/3 (cos(90° - 10°) + i sin(90° - 10°))
z₁/z₂ = 5 (cos(80°) + i sin(80°))
so that z₁ is scaled by a factor of 1/3 and is rotated 10° clockwise.
Yes this is using the transitive property
Point A leads to point B, B goes to C, so overall A goes to C. Think of it connecting a chain.
Nice job on getting the correct answer.
Answer:
gradient m is 2
Step-by-step explanation:
the equation is y=mx+c therefore m is 2.
