Question

Use the forward substitution method to obtain the closed form formula for the recurrence relation

Answer 1

Answer:

$a_n = 2^n -1$

Step-by-step explanation:

We are given the following information:

$a_n = 2a_{n-1} + 1, a_0 = 0$

We will now evaluate values for n =1, 2, 3, 4, 5 and so on.

By forward substitution method:

$a_1 = 2a_0 + 1 = 0 + 1 = 1\\a_2 = 2a_1 + 1 = 2(1) + 1 =3\\a_3 = 2a_2 + 1 = 2(3) + 1 = 7\\a_4 = 2a_3 + 1 = 2(7) + 1 = 15\\a_5 = 2a_4 + 1 = 2(15) + 1 =31$

If we continue in this manner, we can see a general trend and we can say that

$a_n = 2^n -1$

This is the solution for given recurrence relation.