The probability that a random alcoholic can kick the habit without professional help is 0.273 .
<h3>What is Probability ?</h3>
Probability is the study of likeliness of an event to happen.
It has a range of 0 to 1 , where 0 indicates uncertainty and 1 indicates certainty.
It is given that
The alcoholics that need professional help to stop drinking is 72.7 %
Therefore the probability of this is 72.7 /100 = 0.727
The probability that they will not need professional help is given by
q = 1 - p
q = 1 -0.727
q = 0.273
Therefore the probability that a random alcoholic can kick the habit without professional help is 0.273 .
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Answer: Hello!
Let's start with the word TRISKAIDEKAPHOBIA wich has 17 letters (some of them repeat, but it does not matter in this problem)
We want to know how many permutations we can do with 17 letters: then think this way, Lets compose a word. The first letter of this word has 17 options, the second letter of the word has 16 options (you already took one of the set) the third letter of the word has 15 options, and so on.
The total number of permutations is the product of the number of options that you have for each letter, this is:
17*16*15*14*....*3*2*1 = 17! = 3.6e+14
(b) FLOCCINAUCINIHILIPILIFICATION now we have 30 letters in total, using the same reasoning as before, here we have 30! permutations; this is
30! = 2.65e+32
(c) PNEUMONOULTRAMICROSCOPICSILICOVOLCANOCONIOSIS: now there are 47 letters.
then P = 47! = 2.59e+59
(d) DERMATOGLYPHICS: here are 18 letters, then:
p = 18! = 6.4e+15
Answer:
$14.75
Step-by-step explanation:
Y=1/3[-3]-2 I think is the answer
