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3 years ago

I need help ??? I don't understand it I have problem with math a lot I need this done by spring break

Mathematics

1 answer:

Romashka-Z-Leto [24]3 years ago

5 0

You have to make a proportion with a part whole and percent the whole is the money amount the part is the amount of people the percent is well the percent<span />

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The doubling period of a bacterial population is 20 20 minutes. At time t = 100 t=100 minutes, the bacterial population was 9000

Nuetrik [128]

Answer:

The initial population was 2810

The bacterial population after 5 hours will be 92335548

Step-by-step explanation:

The bacterial population growth formula is:

$P = P_0 \times e^{rt}$

where P is the population after time t, $P_0$ is the starting population, i.e. when t = 0, r is the rate of growth in % and t is time in hours

Data: The doubling period of a bacterial population is 20 minutes (1/3 hour). Replacing this information in the formula we get:

$2 P_0 = P_0 \times e^{r 1/3}$

$2 = e^{r \; 1/3}$

$ln 2 = r \; 1/3$

$ln 2 \times 3 = r$

$2.08 \% = r$

Data: At time t = 100 minutes (5/3 hours), the bacterial population was 90000. Replacing this information in the formula we get:

$90000 = P_0 \times e^{2.08 \; 5/3}$

$\frac{9000}{e^{2.08 \; 5/3}} = P_0$

$2810 = P_0$

Data: the initial population got above and t = 5 hours. Replacing this information in the formula we get:

$P = 2810 \times e^{2.08 \; 5}$

$P = 92335548$

3 0

3 years ago

Ravi makes 9 dollars for each hour of work. write an equation to represent his total pay p after working h hours.

dezoksy [38]

P=9h
just plug in the variables

7 0

3 years ago

Can anyone solve the last question?

sesenic [268]

As stated in (i), the equation of the line is: ln y = -0.015x + .26
(By the way, I checked your answers for parts (i) and (ii) and they are both correct)

(iii)
Plug in (1.1) for y and solve:
ln (1.1) = -0.015x + .26
0.095 = -0.015x + .26
-0.165 = - 0.015x
10.979 = x

Answer: x = 10.979

7 0

3 years ago

Graph the function r(x) = -1/4 |x|

Free_Kalibri [48]

Here is your function graphed