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Nat2105 [25]
3 years ago
9

Carl has three lengths of cable, 5/6 yard long, 1/4 yard long, and 2/3 yard long. If he uses 1 yard of cable, how much cable is

left?
Please explain how you did it :3
Mathematics
1 answer:
Dafna1 [17]3 years ago
3 0
He would have 9/12 yards left over because you have to create a common denominator which would be 12. so for 5/6 you would multiply by 2 so you have 10/12. 1/4 you have to multiply by 3 so you get 3/12. and 2/3 you have to multiply by 4 so you get 8/12. then you add them 10/12+3/12+8/12 = 21/12 which simplifies to 1 9/12 and because he used 1 yard he is left with 9/12.
final answer: 9/12 yards
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7. Eduardo has $150 in savings and makes $9.75 per hour. Jennifer has $90 in savings and earns $15.25 for each
Stells [14]

Answer:

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Step-by-step explanation:

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4 0
3 years ago
7.3 homework help me
olga_2 [115]

Answer:

1. Yes

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by SAS

2. Yes

∆ABC ~ ∆PQR

by SSS

3. Yes

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4. Yes

∆DJK ~ ∆PZR

by SAS

5. Yes

∆RTU ~ ∆STL

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5. Yes

∆JKL ~ ∆XYW

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6. No

7. Yes

∆BEF ~ ∆NML

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8. Yes

∆GHI ~ ∆QRS

by SSS

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Step-by-step explanation:

1. RS/WS=ST/SX and m<RST=m<WSX

2. AB/PQ=8/6=4/3

BC/QR=AC/PR=12/9=4/3

AB/PQ=BC/QR=AC/PR

3. ST/JP=10/15=2/3

SU/JM=14/21=2/3

ST/JP=2/3=SU/JM

and m<TSU=70°=m<PJM

4. DK/PR=8/4=2

JK/ZR=18/9=2

DK/PR=2=JK/ZR

and m<DKJ=65°=m<PRZ

5. RT/ST=UT/LT

and m<RTU=m<STL

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JL/XW=36/24=3/2

KL/YW=10/9≠3/2=JL/XW

7. BF/NL=24/16=3/2

BE/NM=39/26=3/2

BF/NL=3/2=BE/NM

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8. GH/QR=32/20=8/5

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GI/QS=24/15=8/5

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Simplifying the fraction on the right side of the equation:

x/33=2/3

Solving for x: Multiplying both sides of the equation by 33:

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8 0
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