9:3: 3:1 is the phenotypic ratio showing traits as black and long hair : black and short hair: chestnut and long hair: chestnut and short hair when a chestnut horse heterozygous for pacing and hair length with a hybrid horse.
Explanation:
Dominant trait = black hair colour (BB,Bb), trotting (TT,Tt) , long hair (LL,Ll)
recessive trait = chesnut hair colour (bb), pacing gait (tt), short hair(ll)
cross between chestnut horse heterozygous for pacing and hair length will have alleles as BbLl
alleles for hybrid horse will also be heterozygous Bb, Ll
Punnett square to show the cross:
BL Bl bL bl
BL BBLL BBLl BbLL BbLl
Bl BBLl BBll BbLl Bbll
bL BbLL BbLl bbLL bbLl
bl BbLl Bbll bblL bbll
phenotype ratio
black and long hair : black and short hair: chestnut and long hair: chestnut and short hair
9:3: 3:1 is the phenotype ratio.
Answer:
Explanation:
If the patient makes any statement that includes the wrong measures or actions that should be taken to prevent side effects then it is clear that they need further teaching. On the basis of treatment for psychosis with perphenazine then such wrong statement may be something like the following: "If I have a dry mouth then I need to take lozenges or eat hard candy for a period of 2 weeks"
Carbon fixation.<span> A </span><span><span>\text {CO}_2<span>CO<span><span>2</span><span></span></span></span></span>C, O, start subscript, 2, end subscript</span><span> molecule combines with a five-carbon acceptor molecule, ribulose-1,5-bisphosphate (</span>RuBP<span>). This step makes a six-carbon compound that splits into two molecules of a three-carbon compound, 3-phosphoglyceric acid (3-PGA). This reaction is catalyzed by the enzyme RuBP carboxylase/oxygenase, or </span>rubisco<span>.</span>
4. All of the above.
5. Some plant-like protests undergo sexual reproduction.
6. Animal-like protists with a flagellum.
7. True.
The answer is <span>0.132606 amu.</span>
The mass defect (Δm) is the total mass of protons and neutrons minus the mass of the atom.
<span>mass of an oxygen-16 atom: 15.994914 amu
mass of a proton: 1.00728 amu
mass of a neutron: 1.00866 amu
</span>
An oxygen atom has 8 protons and 8 neutrons. Therefore:
Δm = 8 · 1.00728 + 8 · 1.00866 - <span>15.994914 = 8.05824 + 8.06928 - 15.994914 = 0.132606 amu
</span>
