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Lesechka [4]
3 years ago
5

A woman who is a carrier for XLA marries a man who does not have the disorder. They have four sons. How many could be expected t

o have XLA?
Biology
1 answer:
ss7ja [257]3 years ago
8 0

Answer:

Their sons have 50% chance of having XLA.

Explanation:

X-linked agammaglobulinemia (XLA) is a genetic disorder that affects person immune system or ability of the body to fight against Infections. A person with XLA disease have few B cells which are specialized white blood cells for fighting Infections. If a female have XLA disease she has 50% chance of transmitting disease to their sons. A male has 50% chance of having XLA and female 25% chance.

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In mice, the presence of a dominant A allele results in the agouti pattern of fur color, whereas the aa homozygous recessive res
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Answer:

Although no genotype is given in the question, the answer may vary, depending on which genes are available:

Genotype _ _| _ _| c c (phenotype: albino).

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Explanation:

Based on the information give, the AA and Aa genotypes produce the agouti color pattern, whereas the aa genotype results in a solid color pattern.

The BB and Bb genotypes result in black fur color, while bb results in brown fur color.

The CC and Cc genotypes turn on the color in the other pairs of genes. Meanwhile, the cc genotype prevents any colors to be shown, or it leads to albino.

Here, we have three pairs of alleles (_ _| _ _| _ _), represented by six underlines. The first, second and third two underlines respectively show the loci of the pair of alleles that results in agouti color vs solid color, black vs brown color, and any color of the first two pairs to be shown vs not to be shown (albino).

Whenever cc is available, the mice with the genotype _ _| _ _| c c has the albino phenotype.

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