Answer:
X-linked recessive inheritance
Explanation:
Since the disease is primarily present in males vs females, it is a s.ex linked disease.
In X-linked recessive inheritance, males tend to get disease b/c they only have one x (the other is y) which means if they get the bad "x" copy from mom then they definetely will get the disease.
Females can be carriers b/c they are XX. If they get a good copy from mom and suppose a bad copy from dad, they can still be healthy b/c the good copy is dominant. They will be carriers (cuz they have the bad copy) but themselves wont have the disease.
Answer: A. true
Explanation: The phenotype is the physical characteristics of a person. So, if a person has brown eyes, which may be a characteristic that is dominant, then they would have a genotype of BB or Bb. The reason why Bb, heterozygous, is not a different color is because the recessive b does not affect the dominant B allele.
Hope this helps!!!
Answer: they are on diffrent parts of the chain
Explanation:
Two major types of organelle in eukaryotic cells, mitochondriaand plastids such aschloroplasts, originated as bacterial endosymbionts.
Explanation:
The phenotypes and genotypes of the progeny can be determined by a dihybrid cross of the parents.
The heterozygous male will have the genotype 'SSww' and the heterozygous female will have the genotype 'ssWW'.
When crossed, the F1 offsprings will have a hybrid genotype of 'SsWw'. These offsprings are heterozygous with spotted skin and wooly hair.
On self-crossing of the F1 hybrids, we find four different combinations of the alleles- SW, Sw, SW and sw. The probability of getting each of these combinations is 1/4.
Hence, the probability of any dihybrid type is 1 out of the 16 possible genotypes. Using Punnet square, we find
9 SSWW: 3 SSww: 3 ssWW : 1 ssww
This is the phenotypic ratio of the offsprings.
The ratio of the possible genotypes will be 1:2:1:2:4:2:1:2:1.
