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allochka39001 [22]
4 years ago
6

If aₙ = 3(3)ⁿ⁻1 , what is S₃?

Mathematics
2 answers:
dlinn [17]4 years ago
8 0

Answer:

S3 = 39

Step-by-step explanation:

* an = 3(3)^(n-1) is a geometric sequence

* The general rule of the geometric sequence is:

 an = a(r)^(n-1)

Where:

a is the first term

r is the common difference between each consecutive terms

n is the position of the term in the sequence

The rules means:

- a1 = a , a2 = ar , a3 = ar² , a4 = ar³ , ........................

∵ an = 3(3)^(n-1)

∴ a = 3 and r = 3

∴ a1 = 3

∴ a2 = 3(3) = 9

∴ a3 = 3(3)² = 27

* S3 = a1 + a2 + a3

∴ S3 = 3 + 9 + 27 = 39

<em>Note: </em>

We can use the rule of the sum:

Sn = a(1 - r^n)/(1 - r)

S3 = 3(1 - 3³)/1 - 3 = 3(1 - 27)/-2 = 3(-26)/-2 =3(13) = 39

neonofarm [45]4 years ago
3 0

Answer:

The correct answer is S₃  = 39

Step-by-step explanation:

It is given that,

aₙ = 3(3)ⁿ⁻¹

<u>To find a₁ </u>

a₁ = 3(3)¹⁻¹ = 3(3)°

= 3 * 1 = 3

<u>To find a₂ </u>

a₂ = 3(3)²⁻¹ = 3(3)¹

= 3 * 3 = 9

<u>To find a₃ </u>

a₃ = 3(3)³⁻¹ = 3(3)²

= 3 * 9 = 27

<u>To find the value of S₃ </u>

S₃ = a₁ + a₂ + a₃

 = 3 + 9 + 27 = 39

Therefore the correct answer is S₃  = 39

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