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3 years ago

1/6 divided by 1/12 HELP

Mathematics

2 answers:

Vadim26 [7]3 years ago

7 0

Answer:

Step-by-step explanation:

1/6 divided by 1/12

=1/6*12/1

which if you divide 12 by six, equals 2

mariarad [96]3 years ago

3 0

Answer:

0.01388888888 as a decimal

Step-by-step explanation:

69/5000 as a fraction

1.38 as a percent

As a decimal its simplified as 0.0138

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SOMEONE PLEASE ANSWER THIS ASAP FOR BRAINLIEST!!!!!!

Gennadij [26K]

The answer would be D. D is the correct answer because the x which is 100 is equal to the amount of U.S dollars and H(x) is equal to the amounts of euros. So H(100)= 75 can signify that she can exchange 100 U.S dollars for 75 euros.

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4 years ago

Rachel has 8 coins. The amount of her coins is 74 cents what coins does rachel have

Brums [2.3K]

Answer:

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Step-by-step explanation:

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4 years ago

What is the answer for 4y^2=81

Elena L [17]

Answer:
either y = 4.5
or y = -4.5

Explanation:
To get the solution, we will need to isolate the y on one side of the equation.
This can be done as follows:
4y² = 81

 $\frac{4y^2}{4} = \frac{81}{4}$

y² = 20.25

y = +/- √(20.25)
either y = +√(20.25) = 4.5
or y = -√(20.25) = -4.5

Since there are no restrictions on the value of y, therefore, both answers would be accepted

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3 0

3 years ago

Read 2 more answers

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ExtremeBDS [4]

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3 years ago

Given the sequence 1/2 ; 4 ; 1/4 ; 7 ; 1/8 ; 10;.. calculate the sum of 50 terms

miv72 [106K]

Hint :-

Break the given sequence into two parts .
Notice the terms at gap of one term beginning from the first term .They are like $\dfrac{1}{2},\dfrac{1}{4},\dfrac{1}{8}$ . Next term is obtained by multiplying half to the previous term .
Notice the terms beginning from 2nd term , $4,7,10,13$ . Next term is obtained by adding 3 to the previous term .

Solution :- 

We need to find out the sum of 50 terms of the given sequence . After splitting the given sequence ,

$\implies S_1 = \dfrac{1}{2},\dfrac{1}{4},\dfrac{1}{8}$ .

We can see that this is in Geometric Progression where 1/2 is the common ratio . Calculating the sum of 25 terms , we have ,

$\implies S_1 = a\dfrac{1-r^n}{1-r} \\\\\implies S_1 = \dfrac{1}{2}\left[ \dfrac{1-\bigg(\dfrac{1}{2}\bigg)^{25}}{1-\dfrac{1}{2}}\right]$

Notice the term $\dfrac{1}{2^{25}}$ will be too small , so we can neglect it and take its approximation as 0 .

$\implies S_1\approx \cancel{ \dfrac{1}{2} } \left[ \dfrac{1-0}{\cancel{\dfrac{1}{2} }}\right]$

$\\\implies \boxed{ S_1 \approx 1 }$

$\rule{200}2$

Now the second sequence is in Arithmetic Progression , with common difference = 3 .

$\implies S_2=\dfrac{n}{2}[2a + (n-1)d]$

Substitute ,

$\implies S_2=\dfrac{25}{2}[2(4) + (25-1)3] =\boxed{ 908}$

Hence sum = 908 + 1 = 909

7 0

3 years ago