QUESTION 5
The side length of the first tra-pezoid and the second tra-pezoid are in the ratio .
To find the corresponding ratio of their area, we square each term in the ratio.
The ratio of the area of the first figure, to the ratio of the area of the second is
QUESTION 6
The side length of the first figure and the second figure are in the ratio .
To find the corresponding ratio of their area, we square each term in the ratio.
The ratio of the area of the first figure, to the ratio of the area of the second figure is
QUESTION 7
Let represent the height of this triangle.
This implies that;
The area of the triangle is
The base is 9 ft and the height is 3 ft.
We substitute these values to obtain;
to the nearest tenth.
QUESTION 8
The area of a parallelogram is
Let h represent the height of this parallelogram.
The area of the parallelogram is
to the nearest tenth.
Answer:50000
Step-by-step explanation:
It is not a very tough question as it has all the information's required to find the necessary answer. It is already given that 82 1/2% of a certain number is 330. It is required to find the unknown number. So we have to create an equation with a single unknown number.
Let us assume the number to be = x
then we can easily write the equation as given below.
82 1/2% x = 330
(165/4)%x = 330
(165/400)x = 330
x = (330 * 400)/165
= 2 * 400
= 800
So the unknown number is 800.
Let x represent the height of the person and y the weight.
y - 180 = (80 - 180)/(4 - 6) (x - 6)
y - 180 = -100/-2 (x - 6) = 50(x - 6) = 50x - 300
y = 50x - 300 + 180 = 50x - 120
y = 50x - 120
A person 5.5 feet tall will weigh 50(5.5) - 120 = 275 - 120 = 155 pounds.